42. Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.


The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped. Thanks Marcos for contributing this image!

Example:

Input: [0,1,0,2,1,0,1,3,2,1,2,1]
Output: 6

AC code:

class Solution {
public:
    int trap(vector<int>& height) {
        int left = 0;
        int right = height.size() - 1;
        int leftMax = 0;
        int rightMax = 0;
        int res = 0;
        while (left < right) {
            if (height[left] < height[right]) {
                leftMax = max(leftMax, height[left]);
                res += leftMax - height[left];
                left++;
            } else {
                rightMax = max(rightMax, height[right]);
                res += rightMax - height[right];
                right--;
            }
        }
        return res;
    }
};
Runtime: 4 ms, faster than 100.00% of C++ online submissions for Trapping Rain Water.
永远渴望,大智若愚(stay hungry, stay foolish)
原文地址:https://www.cnblogs.com/h-hkai/p/9799362.html