List双向链表容器

//list双向链表中任意位置的元素查找,
//插入和删除都具有高效的常数阶算法时间复杂度O(1).
#include<iostream>
#include<cstdio>
#include<list>

using namespace std;

struct student
{
    char *name;
    int age;
    char *city;
};

void print(list<student>&l)
{
    list<student>::iterator i;
    for(i = l.begin(); i != l.end(); i++)
    {
        cout<<(*i).name<<" ";
        cout<<(*i).age<<" ";
        cout<<(*i).city<<" "<<endl;
    }
}

int main()
{
    student s[] = {
            {"张三", 18, "浙江"},       //插入元素
            {"李四", 19, "北京"},
            {"王二", 18, "上海"}
            };

    list<student>l;
    l.push_back(s[0]);
    l.push_back(s[1]);
    l.push_back(s[2]);

    student x = {"六四", 19, "新疆"};

    l.push_front(x);                    //插入到首位置,复杂度为O(1)
    l.insert(l.begin(), x);             //插入到任意位置,复杂度为O(1)

    //l.pop_front();                    //删除首位置元素
    //l.pop_back();                     //删除韦位置元素

    l.erase(l.begin());

    //l.remove(2);                      //删除所有值为2的元素,结构体未知方法
    //l.clear();                        //删除所有元素
    //l.erase(l.begin(), l.end());      //删除区间的元素,方法为完全掌握

    print(l);

    list<student>::reverse_iterator ri;
    for(ri = l.rbegin(); ri != l.rend(); ri++)
        cout<<(*ri).name;

    getchar();

    return 0;
}

链表归并

//链表归并的查考代码如下例所示:
#include<iostream>
#include<cstdio>
#include<list>

using namespace std;

struct student
{
    char *name;
    int age;
    char *city;
};

void print(list<int> l)
{
    list<int>::iterator i;
    for(i = l.begin(); i != l.end(); i++)
        cout<<*i<<" ";
    cout<<endl;
}

int main()
{
    list<int>l1;
    for(int j = 10; j >= 0; j--)
        l1.push_back(j);

    list<int>l2;
    list<int>::iterator ii;
    ii = l2.begin()++;
    l2.splice(l2.begin(), l1);              //将l1的全部元素归并到L2,L1清空
    l1.splice(l1.begin(), l2, ii);          //将L2的ii位置的元素归并到L1,L2原元素删除
    swap(l1, l2);                           //交换L1,L2
    l1.sort();                              //排序
    l1.push_back(8);
    l1.push_back(8);
    l1.push_back(35);
    l1.push_back(30);
    l1.unique();                            //删除连续重复元素
    l2.merge(l1);                           //L1归并到L2,需要两个链表均排序,最后的结果也为排序的结果
    print(l1);
    print(l2);
    getchar();

    return 0;
}
永远渴望,大智若愚(stay hungry, stay foolish)
原文地址:https://www.cnblogs.com/h-hkai/p/8320509.html