reverse number

class Solution {
public:
int reverse(int x) {
  bool negative_flag=false;
if(x==INT_MIN)
  return 0;
if(x<0)
{
  x=-x;
  negative_flag=true;
}
long long result=0;
while(x!=0)
{
  result=result*10+x%10;
  x=x/10;
}
if(result>INT_MAX)
  return 0;
if(negative_flag)
  return -result;
else
  return result;
}
};

原文地址:https://www.cnblogs.com/h-haha/p/4490812.html