第二次上机练习

1.编写程序, 输入变量x的值,如果是1,输出x=1,如果是5,输出x=5,如果是 10,输出 x=10,除了以上几个值,都输出x=none。(知识点:if条件语句)

 1 package text;
 2 import java.util.Scanner;
 3 public class ZuoYe {
 4 
 5     public static void main(String[] args) {
 6         // TODO Auto-generated method stub
 7        Scanner input = new Scanner(System.in);
 8        System.out.println("输入x的值:");
 9         int x = input.nextInt();
10             if (x==1){
11                 System.out.println("x=1");
12      }else if(x==5){
13                 System.out.println("x=5");
14      }else if (x==10){
15                 System.out.println("x=10");
16      } else {
17                 System.out.println("x=none");
18         }
19 
20     }
21 
22 }

2.用switch结构实现第1题

 1 package text;
 2 import java.util.Scanner;
 3 public class ZuoYe {
 4 
 5     public static void main(String[] args) {
 6         // TODO Auto-generated method stub
 7        Scanner input = new Scanner(System.in);
 8        System.out.println("输入x的值:");
 9         int x = input.nextInt();
10         switch(x){
11             case 1:
12                 System.out.println("x=1");
13                 break;
14             case 5:
15                 System.out.println("x=5");
16                 break;
17             case 10:
18                 System.out.println("x=10");
19                 break;
20             default:
21                 System.out.println("x=none");
22                 break;
23         }
24 
25     }
26 
27 }

 3.判断一个数字是否能被5和6同时整除(打印能被5和6整除),或只能被5整除(打印能被5整 除),或只能被6整除,(打印能被6整除),不能被5或6整除,(打印不能被5或6整除)

 1 package text;
 2 import java.util.Scanner;
 3 public class ZuoYe {
 4 
 5     public static void main(String[] args) {
 6         // TODO Auto-generated method stub
 7        Scanner input = new Scanner(System.in);
 8        System.out.println("输入x的值:");
 9         int x = input.nextInt();
10            if (x%5==0&&x%6==0){
11                System.out.println("打印能被5和6整除");
12            }else if(x%5==0&&x%6!=0){
13                System.out.println("打印能被5整除");
14            }else if (x%6==0&&x%5!=0){
15                System.out.println("打印能被6整除");
16         } else {
17             System.out.println("打印不能被5和6整除");
18         }
19     }
20 }

4.输入一个0~100的分数,如果不是0~100之间,打印分数无效,根据分数等级打印 A(90-100),B(80-89),C,D,E(知识点:条件语句if elseif)

 1 package text;
 2 import java.util.Scanner;
 3 public class ZuoYe {
 4 
 5     public static void main(String[] args) {
 6         // TODO Auto-generated method stub
 7        Scanner input = new Scanner(System.in);
 8        System.out.println("输入一个1~100的分数:");
 9         int x = input.nextInt();
10            if (x>=90&&x<=100){
11                  System.out.println("分数等级打印为A");
12            }else if(x>=80&&x<=89){
13                  System.out.println("分数等级打印为B");
14            }else if(x>=70&&x<=79){
15                  System.out.println("分数等级打印为C");
16            }else if(x>=60&&x<=69){
17                  System.out.println("分数等级打印为D");
18            }else if(x>=50&&x<=59){
19                  System.out.println("分数等级打印为E");
20            }else {
21                  System.out.println("打印分数无效");
22         }
23     }
24 }

5.输入三个整数x,y,z,请把这三个数由小到大输出(知识点:条件语句)

 1 package text;
 2 import java.util.Scanner;
 3 public class ZuoYe {
 4 
 5     public static void main(String[] args) {
 6         // TODO Auto-generated method stub
 7        Scanner input = new Scanner(System.in);
 8        System.out.println("输入三个整数x,y,z:");
 9         int x = input.nextInt();
10         int y = input.nextInt();
11         int z = input.nextInt();
12         if(x>y&&y>z){
13             System.out.println(z+"<"+y+"<"+x);
14         }else if(x>z&&z>y){
15             System.out.println(y+"<"+z+"<"+x);
16         }else if(y>x&&x>z){
17             System.out.println(z+"<"+x+"<"+y);
18         }else if(y>z&&z>x){
19             System.out.println(x+"<"+z+"<"+y);
20         }else if(z>x&&x>y){
21             System.out.println(y+"<"+x+"<"+z);
22         }else if(z>y&&y>x){
23             System.out.println(x+"<"+y+"<"+z);
24         }
25     
26     }
27 }

 

原文地址:https://www.cnblogs.com/gwz-1314/p/12573762.html