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problem

solution

codes

//并查集模板
#include<iostream>
using namespace std;
int fa[5010];
void init(int n){for(int i = 1; i <= n; i++)fa[i]=i;}
int find(int x){return x==fa[x]?x:fa[x]=find(fa[x]);}
void merge(int x, int y){x=find(x);y=find(y);if(x!=y)fa[x]=y;}
int main(){
    int n, m, p;
    cin>>n>>m>>p;
    init(n);
    for(int i = 1; i <= m; i++){
        int a, b;  cin>>a>>b;  merge(a,b);
    }
    for(int i = 1; i <= p; i++){
        int a, b;  cin>>a>>b;
        if(find(a)==find(b))cout<<"Yes
";
        else cout<<"No
";
    }
    return 0;
}
原文地址:https://www.cnblogs.com/gwj1314/p/9444792.html