原题:
Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123 Output: 321
Example 2:
Input: -123 Output: -321
Example 3:
Input: 120 Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
思路:
用long型保存反转结果,进行溢出判断.
c++代码实现:
class Solution { public: int reverse(int x) { long res = 0; while(x){ res = res*10 + x%10; x = x/10; } return (res >INT_MAX || res <INT_MIN)?0:res; } };