112. Path Sum Java Solutin

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
             / 
            4   8
           /   / 
          11  13  4
         /        
        7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

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 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 public class Solution {
11     public boolean hasPathSum(TreeNode root, int sum) {
12         if(root == null) return false;
13         if(root.left == null && root.right ==null && sum == root.val)
14             return true;
15         else{
16             return hasPathSum(root.left,sum-root.val) || hasPathSum(root.right,sum-root.val);
17         }
18     }
19 }
原文地址:https://www.cnblogs.com/guoguolan/p/5396732.html