剑指Offer_编程题_20

题目描述

从上往下打印出二叉树的每个节点,同层节点从左至右打印。
 
/*
struct TreeNode {
	int val;
	struct TreeNode *left;
	struct TreeNode *right;
	TreeNode(int x) :
			val(x), left(NULL), right(NULL) {
	}
};*/
class Solution {
public:
    vector<int> PrintFromTopToBottom(TreeNode* root) {
        queue<TreeNode*>q;
        vector<int>vt;
        if(root == NULL)
            return vt;
        q.push(root);
        vt.push_back(root->val);
        while(!q.empty()){
            TreeNode* tmp = q.front();
            q.pop();
            if(tmp->left != NULL){
                vt.push_back(tmp->left->val);
                q.push(tmp->left);
            }
            if(tmp->right != NULL){
                vt.push_back(tmp->right->val);
                q.push(tmp->right);
            }
        }
        return vt;
    }
};

  

原文地址:https://www.cnblogs.com/grglym/p/8964367.html