HDUOJ--1865 1string

1sting

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2372    Accepted Submission(s): 947


Problem Description
You will be given a string which only contains ‘1’; You can merge two adjacent ‘1’ to be ‘2’, or leave the ‘1’ there. Surly, you may get many different results. For example, given 1111 , you can get 1111, 121, 112,211,22. Now, your work is to find the total number of result you can get.
 
Input
The first line is a number n refers to the number of test cases. Then n lines follows, each line has a string made up of ‘1’ . The maximum length of the sequence is 200.
 
Output
The output contain n lines, each line output the number of result you can get .
 
Sample Input
3
1
11
11111
 
Sample Output
1
2
8
 
Author
z.jt
 
Source
Recommend
lcy
 简单大数题....
代码:
 1 #include<iostream>
 2 #include<string>
 3 #define maxn 50
 4 #define  len 200
 5 using namespace std;
 6 int arr[len][maxn+1]={{1},{1}};
 7 int main()
 8 {
 9     int i,j,s,c,t;
10     string n ;
11     for(i=2;i<=len;i++)
12     {
13         for(c=j=0;j<=maxn;j++)
14         {
15           s=arr[i-1][j]+arr[i-2][j]+c;
16           arr[i][j]=s%10;
17           c=(s-arr[i][j])/10;
18         }
19     }
20     cin>>t;
21     while(t--)
22     {
23         cin>>n;
24         for(i=maxn;arr[n.size()][i]==0;i--);
25         for(j=i;j>=0;j--)
26         {
27             printf("%d",arr[n.size()][j]);
28         }
29         puts("");
30     }
31 return 0;
32 }
View Code
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原文地址:https://www.cnblogs.com/gongxijun/p/3236426.html