hdu 1907 John（anti nim）

John

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 4704    Accepted Submission(s): 2720

Problem Description

Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. And so on. Please note that each player has to eat at least one M&M during his turn. If John (or his brother) will eat the last M&M from the box he will be considered as a looser and he will have to buy a new candy box.

Both of players are using optimal game strategy. John starts first always. You will be given information about M&Ms and your task is to determine a winner of such a beautiful game.

 

Input

The first line of input will contain a single integer T – the number of test cases. Next T pairs of lines will describe tests in a following format. The first line of each test will contain an integer N – the amount of different M&M colors in a box. Next line will contain N integers Ai, separated by spaces – amount of M&Ms of i-th color.

Constraints:
1 <= T <= 474,
1 <= N <= 47,
1 <= Ai <= 4747

 

Output

Output T lines each of them containing information about game winner. Print “John” if John will win the game or “Brother” in other case.

 

Sample Input

2 3 3 5 1 1 1

 

Sample Output

John Brother

 

Source

 

 

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int t;
    int n;
    int a;
    int i;
    int sum, ones;

    scanf("%d", &t);

    while (t--) {
        scanf("%d", &n);
        sum = 0, ones = 0;
        for (i = 0; i < n; ++i) {
            scanf("%d", &a);
            sum ^= a;
            if (a == 1) {
                ++ones;
            }
        }

        //win : t0, s1, s2
        //lose : s0, t2
        if (sum == 0) {//t
            if (n - ones == 0) {//t0
                printf("John
");
            } else {//t2
                printf("Brother
");
            }
        } else {//s
            if (n - ones == 0) {//s0
                printf("Brother
");
            } else {//s1, s2
                printf("John
");
            }
        }
    }

    return 0;
}