网络流

1.最大流

ps:直接以题目来看模板的使用

POJ - 1459 Power Network(最大流)(模板)

d.看了好久,囧。

n个节点,np个源点,nc个汇点,m条边(对应代码中即节点u 到节点v 的最大流量为z)

求所有汇点的最大流。

s.多个源点,多个汇点的最大流。

建立一个超级源点、一个超级汇点,然后求超级源点到超级汇点的最大流即可。

c.SAP邻接矩阵形式:

/*
SAP算法(矩阵形式)
结点编号从0开始
*/
#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

const int MAXN=128;
int maze[MAXN][MAXN];
int gap[MAXN],dis[MAXN],pre[MAXN],cur[MAXN];
int sap(int start,int end,int nodenum){
    memset(cur,0,sizeof(cur));
    memset(dis,0,sizeof(dis));
    memset(gap,0,sizeof(gap));
    int u=pre[start]=start,maxflow=0,aug=-1;
    gap[0]=nodenum;
    while(dis[start]<nodenum){
        loop:
            for(int v=cur[u];v<nodenum;v++)
                if(maze[u][v]&&dis[u]==dis[v]+1){
                    if(aug==-1||aug>maze[u][v])aug=maze[u][v];
                    pre[v]=u;
                    u=cur[u]=v;
                    if(v==end){
                        maxflow+=aug;
                        for(u=pre[u];v!=start;v=u,u=pre[u]){
                            maze[u][v]-=aug;
                            maze[v][u]+=aug;
                        }
                        aug=-1;
                    }
                    goto loop;
                }
            int mindis=nodenum-1;
            for(int v=0;v<nodenum;v++)
                if(maze[u][v]&&mindis>dis[v]){
                    cur[u]=v;
                    mindis=dis[v];
                }
            if((--gap[dis[u]])==0)break;
            gap[dis[u]=mindis+1]++;
            u=pre[u];
    }
    return maxflow;
}

int main(){
    int n,np,nc,m;//节点总数,源点,汇点,边数
    int u,v,z;//节点u,节点v,最大流量z
    char str[5];//处理空格
    int sp,sc;//超级源点,超级汇点

    while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
        memset(maze,0,sizeof(maze));
        for(int i=0;i<m;++i){
            scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
            maze[u][v]=z;
        }

        //建立超级源点
        sp=n++;
        for(int i=0;i<np;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            maze[sp][u]=z;
        }
        //建立超级汇点
        sc=n++;
        for(int i=0;i<nc;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            maze[u][sc]=z;
        }
        printf("%d
",sap(sp,sc,n));
    }
    return 0;
}
View Code

c2.SAP邻接矩阵形式2:

/*
保留原矩阵,可用于多次使用最大流
SAP邻接矩阵形式
点的编号从0开始
增加个flow数组,保留原矩阵maze,可用于多次使用最大流
*/
#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

const int MAXN=128;
int maze[MAXN][MAXN];
int gap[MAXN],dis[MAXN],pre[MAXN],cur[MAXN];
int flow[MAXN][MAXN];//存最大流的容量
int sap(int start,int end,int nodenum){
    memset(cur,0,sizeof(cur));
    memset(dis,0,sizeof(dis));
    memset(gap,0,sizeof(gap));
    memset(flow,0,sizeof(flow));
    int u=pre[start]=start,maxflow=0,aug=-1;
    gap[0]=nodenum;
    while(dis[start]<nodenum){
        loop:
            for(int v=cur[u];v<nodenum;v++)
                if(maze[u][v]-flow[u][v]&&dis[u]==dis[v]+1){
                    if(aug==-1||aug>maze[u][v]-flow[u][v])aug=maze[u][v]-flow[u][v];
                    pre[v]=u;
                    u=cur[u]=v;
                    if(v==end){
                        maxflow+=aug;
                        for(u=pre[u];v!=start;v=u,u=pre[u]){
                            flow[u][v]+=aug;
                            flow[v][u]-=aug;
                        }
                        aug=-1;
                    }
                    goto loop;
                }
            int mindis=nodenum-1;
            for(int v=0;v<nodenum;v++)
            if(maze[u][v]-flow[u][v]&&mindis>dis[v]){
                cur[u]=v;
                mindis=dis[v];
            }
            if((--gap[dis[u]])==0)break;
            gap[dis[u]=mindis+1]++;
            u=pre[u];
    }
    return maxflow;
}

int main(){
    int n,np,nc,m;//节点总数,源点,汇点,边数
    int u,v,z;//节点u,节点v,最大流量z
    char str[5];//处理空格
    int sp,sc;//超级源点,超级汇点

    while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
        memset(maze,0,sizeof(maze));
        for(int i=0;i<m;++i){
            scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
            maze[u][v]=z;
        }

        //建立超级源点
        sp=n++;
        for(int i=0;i<np;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            maze[sp][u]=z;
        }
        //建立超级汇点
        sc=n++;
        for(int i=0;i<nc;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            maze[u][sc]=z;
        }
        printf("%d
",sap(sp,sc,n));
    }
    return 0;
}
View Code

c3.ISAP邻接表形式:注意一下边数的范围

/*
ISAP邻接表形式
*/
#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

const int MAXN=128;//点数的最大值
const int MAXM=20500;//边数的最大值(加的双向加,所以是2倍,别忘了加上超级源点和超级汇点(共400条))
const int INF=0x3f3f3f3f;
struct Edge{
    int to,next,cap,flow;
}edge[MAXM];//注意是MAXM
int tol;
int head[MAXN];
int gap[MAXN],dep[MAXN],pre[MAXN],cur[MAXN];
void init(){
    tol=0;
    memset(head,-1,sizeof(head));
}
//加边,单向图三个参数,双向图四个参数
void addedge(int u,int v,int w,int rw=0){
    edge[tol].to=v;edge[tol].cap=w;edge[tol].next=head[u];
    edge[tol].flow=0;head[u]=tol++;
    edge[tol].to=u;edge[tol].cap=rw;edge[tol].next=head[v];
    edge[tol].flow=0;head[v]=tol++;
}
//输入参数:起点、终点、点的总数
//点的编号没有影响,只要输入点的总数
int sap(int start,int end,int N){
    memset(gap,0,sizeof(gap));
    memset(dep,0,sizeof(dep));
    memcpy(cur,head,sizeof(head));
    int u=start;
    pre[u]=-1;
    gap[0]=N;
    int ans=0;
    while(dep[start]<N){
        if(u==end){
            int Min=INF;
            for(int i=pre[u];i!=-1;i=pre[edge[i^1].to])
                if(Min>edge[i].cap-edge[i].flow)
                    Min=edge[i].cap-edge[i].flow;
            for(int i=pre[u];i!=-1;i=pre[edge[i^1].to]){
                edge[i].flow+=Min;
                edge[i^1].flow-=Min;
            }
            u=start;
            ans+=Min;
            continue;
        }
        bool flag=false;
        int v;
        for(int i=cur[u];i!=-1;i=edge[i].next){
            v=edge[i].to;
            if(edge[i].cap-edge[i].flow&&dep[v]+1==dep[u]){
                flag=true;
                cur[u]=pre[v]=i;
                break;
            }
        }
        if(flag){
            u=v;
            continue;
        }
        int Min=N;
        for(int i=head[u];i!=-1;i=edge[i].next)
            if(edge[i].cap-edge[i].flow&&dep[edge[i].to]<Min){
                Min=dep[edge[i].to];
                cur[u]=i;
            }
        gap[dep[u]]--;
        if(!gap[dep[u]])return ans;
        dep[u]=Min+1;
        gap[dep[u]]++;
        if(u!=start)u=edge[pre[u]^1].to;
    }
    return ans;
}

int main(){
    int n,np,nc,m;//节点总数,源点,汇点,边数
    int u,v,z;//节点u,节点v,最大流量z
    char str[5];//处理空格
    int sp,sc;//超级源点,超级汇点

    while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
        init();
        for(int i=0;i<m;++i){
            scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
            addedge(u,v,z);
        }

        //建立超级源点
        sp=n++;
        for(int i=0;i<np;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            addedge(sp,u,z);
        }
        //建立超级汇点
        sc=n++;
        for(int i=0;i<nc;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            addedge(u,sc,z);
        }
        printf("%d
",sap(sp,sc,n));
    }
    return 0;
}
View Code

c4.ISAP+bfs初始化+栈优化:注意一下边数的范围

/*
ISAP+bfs初始化+栈优化
*/
#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

const int MAXN=128;//点数的最大值
const int MAXM=20500;//边数的最大值
const int INF=0x3f3f3f3f;
struct Edge{
    int to,next,cap,flow;
}edge[MAXM];//注意是MAXM
int tol;
int head[MAXN];
int gap[MAXN],dep[MAXN],cur[MAXN];
void init(){
    tol=0;
    memset(head,-1,sizeof(head));
}
void addedge(int u,int v,int w,int rw=0){
    edge[tol].to=v;edge[tol].cap=w;edge[tol].flow=0;
    edge[tol].next=head[u];head[u]=tol++;
    edge[tol].to=u;edge[tol].cap=rw;edge[tol].flow=0;
    edge[tol].next=head[v];head[v]=tol++;
}
int Q[MAXN];
void BFS(int start,int end){
    memset(dep,-1,sizeof(dep));
    memset(gap,0,sizeof(gap));
    gap[0]=1;
    int front=0,rear=0;
    dep[end]=0;
    Q[rear++]=end;
    while(front!=rear){
        int u=Q[front++];
        for(int i=head[u];i!=-1;i=edge[i].next){
            int v=edge[i].to;
            if(dep[v]!=-1)continue;
            Q[rear++]=v;
            dep[v]=dep[u]+1;
            gap[dep[v]]++;
        }
    }
}
int S[MAXN];
int sap(int start,int end,int N){
    BFS(start,end);
    memcpy(cur,head,sizeof(head));
    int top=0;
    int u=start;
    int ans=0;
    while(dep[start]<N){
        if(u==end){
            int Min=INF;
            int inser;
            for(int i=0;i<top;i++)
                if(Min>edge[S[i]].cap-edge[S[i]].flow){
                    Min=edge[S[i]].cap-edge[S[i]].flow;
                    inser=i;
                }
            for(int i=0;i<top;i++){
                edge[S[i]].flow+=Min;
                edge[S[i]^1].flow-=Min;
            }
            ans+=Min;
            top=inser;
            u=edge[S[top]^1].to;
            continue;
        }
        bool flag=false;
        int v;
        for(int i=cur[u];i!=-1;i=edge[i].next){
            v=edge[i].to;
            if(edge[i].cap-edge[i].flow&&dep[v]+1==dep[u]){
                flag=true;
                cur[u]=i;
                break;
            }
        }
        if(flag){
            S[top++]=cur[u];
            u=v;
            continue;
        }
        int Min=N;
        for(int i=head[u];i!=-1;i=edge[i].next)
            if(edge[i].cap-edge[i].flow&&dep[edge[i].to]<Min){
                Min=dep[edge[i].to];
                cur[u]=i;
            }
        gap[dep[u]]--;
        if(!gap[dep[u]])return ans;
        dep[u]=Min+1;
        gap[dep[u]]++;
        if(u!=start)u=edge[S[--top]^1].to;
    }
    return ans;
}

int main(){
    int n,np,nc,m;//节点总数,源点,汇点,边数
    int u,v,z;//节点u,节点v,最大流量z
    char str[5];//处理空格
    int sp,sc;//超级源点,超级汇点

    while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
        init();
        for(int i=0;i<m;++i){
            scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
            addedge(u,v,z);
        }

        //建立超级源点
        sp=n++;
        for(int i=0;i<np;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            addedge(sp,u,z);
        }
        //建立超级汇点
        sc=n++;
        for(int i=0;i<nc;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            addedge(u,sc,z);
        }
        printf("%d
",sap(sp,sc,n));
    }
    return 0;
}
View Code

c5.dinic:注意一下边数的范围

/*
dinic
*/
#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

const int MAXN=128;//点数的最大值
const int MAXM=20500;//边数的最大值
const int INF=0x3f3f3f3f;
struct Edge{
    int to,next,cap,flow;
}edge[MAXM];//注意是MAXM
int tol;
int head[MAXN];
void init(){
    tol=2;
    memset(head,-1,sizeof(head));
}
void addedge(int u,int v,int w,int rw=0){
    edge[tol].to=v;edge[tol].cap=w;edge[tol].flow=0;
    edge[tol].next=head[u];head[u]=tol++;
    edge[tol].to=u;edge[tol].cap=rw;edge[tol].flow=0;
    edge[tol].next=head[v];head[v]=tol++;
}
int Q[MAXN];
int dep[MAXN],cur[MAXN],sta[MAXN];
bool bfs(int s,int t,int n){
    int front=0,tail=0;
    memset(dep,-1,sizeof(dep[0])*(n+1));
    dep[s]=0;
    Q[tail++]=s;
    while(front<tail){
        int u=Q[front++];
        for(int i=head[u];i!=-1;i=edge[i].next){
            int v=edge[i].to;
            if(edge[i].cap>edge[i].flow&&dep[v]==-1){
                dep[v]=dep[u]+1;
                if(v==t)return true;
                Q[tail++]=v;
            }
        }
    }
    return false;
}
int dinic(int s,int t,int n){
    int maxflow=0;
    while(bfs(s,t,n)){
        for(int i=0;i<n;i++)cur[i]=head[i];
        int u=s,tail=0;
        while(cur[s]!=-1){
            if(u==t){
                int tp=INF;
                for(int i=tail-1;i>=0;i--)
                    tp=min(tp,edge[sta[i]].cap-edge[sta[i]].flow);
                maxflow+=tp;
                for(int i=tail-1;i>=0;i--){
                    edge[sta[i]].flow+=tp;
                    edge[sta[i]^1].flow-=tp;
                    if(edge[sta[i]].cap-edge[sta[i]].flow==0)
                        tail=i;
                }
                u=edge[sta[tail]^1].to;
            }
            else if(cur[u]!=-1&&edge[cur[u]].cap>edge[cur[u]].flow&&dep[u]+1==dep[edge[cur[u]].to]){
                sta[tail++]=cur[u];
                u=edge[cur[u]].to;
            }
            else{
                while(u!=s&&cur[u]==-1)
                    u=edge[sta[--tail]^1].to;
                cur[u]=edge[cur[u]].next;
            }
        }
    }
    return maxflow;
}

int main(){
    int n,np,nc,m;//节点总数,源点,汇点,边数
    int u,v,z;//节点u,节点v,最大流量z
    char str[5];//处理空格
    int sp,sc;//超级源点,超级汇点

    while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
        init();
        for(int i=0;i<m;++i){
            scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
            addedge(u,v,z);
        }

        //建立超级源点
        sp=n++;
        for(int i=0;i<np;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            addedge(sp,u,z);
        }
        //建立超级汇点
        sc=n++;
        for(int i=0;i<nc;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            addedge(u,sc,z);
        }
        printf("%d
",dinic(sp,sc,n));
    }
    return 0;
}
View Code

以上算法均取自kuangbin模板,ac时间均不到100ms。

下面补上一个增广路算法(EdmondsKarp算法),但是时间让人捉急,1000多ms

c6.增广路算法(EdmondsKarp算法):

/*
增广路算法(EdmondsKarp算法)
*/
#include<iostream>
#include<stdio.h>
#include<vector>
#include<string.h>
#include<queue>
using namespace std;

const int maxn=128;
const int INF=0x3f3f3f3f;

struct Edge{
    int from,to,cap,flow;
    Edge(int u,int v,int c,int f):from(u),to(v),cap(c),flow(f){}
};

struct EdmondsKarp{
    int n,m;//n好像没用到
    vector<Edge>edges;//边数的两倍
    vector<int>G[maxn];//邻接表,G[i][j]表示结点i的第j条边在e数组中的序号
    int a[maxn];//当起点到i的可改进量
    int p[maxn];//最短路树上p的入弧编号

    void init(int n){
        for(int i=0;i<n;i++)G[i].clear();
        edges.clear();
    }

    void AddEdge(int from,int to,int cap){
        edges.push_back(Edge(from,to,cap,0));
        edges.push_back(Edge(to,from,0,0));//反向弧
        m=edges.size();
        G[from].push_back(m-2);
        G[to].push_back(m-1);
    }

    int Maxflow(int s,int t){
        int flow=0;
        for(;;){
            memset(a,0,sizeof(a));
            queue<int>Q;
            Q.push(s);
            a[s]=INF;
            while(!Q.empty()){
                int x=Q.front();Q.pop();
                for(int i=0;i<G[x].size();i++){
                    Edge &e=edges[G[x][i]];
                    if(!a[e.to]&&e.cap>e.flow){
                        p[e.to]=G[x][i];
                        a[e.to]=min(a[x],e.cap-e.flow);
                        Q.push(e.to);
                    }
                }
                if(a[t])break;
            }
            if(!a[t])break;
            for(int u=t;u!=s;u=edges[p[u]].from){
                edges[p[u]].flow+=a[t];
                edges[p[u]^1].flow-=a[t];
            }
            flow+=a[t];
        }
        return flow;
    }
}EK;

int main(){
    int n,np,nc,m;//节点总数,源点,汇点,边数
    int u,v,z;//节点u,节点v,最大流量z
    char str[5];//处理空格
    int sp,sc;//超级源点,超级汇点

    while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
        EK.init(n+2);//加上下面增加的超级源点和超级汇点
        for(int i=0;i<m;++i){
            scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
            EK.AddEdge(u,v,z);
        }

        //建立超级源点
        sp=n++;
        for(int i=0;i<np;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            EK.AddEdge(sp,u,z);
        }
        //建立超级汇点
        sc=n++;
        for(int i=0;i<nc;++i){
            scanf("%1s%d%1s%d",str,&u,str,&z);
            EK.AddEdge(u,sc,z);
        }
        printf("%d
",EK.Maxflow(sp,sc));
    }
    return 0;
}
View Code

2.最小费用最大流

c.Bellman-Ford

/*
Bellman-Ford
*/
#include<iostream>
#include<stdio.h>
#include<vector>
#include<string.h>
#include<queue>
using namespace std;

const int maxn=1024;
const int INF=0x3f3f3f3f;

struct Edge{
    int from,to,cap,flow,cost;
    Edge(int u,int v,int c,int f,int w):from(u),to(v),cap(c),flow(f),cost(w){}
};

struct MCMF{
    int n,m;
    vector<Edge>edges;
    vector<int>G[maxn];
    int inq[maxn];//是否在队列中
    int d[maxn];//Bellman-Ford
    int p[maxn];//上一条弧
    int a[maxn];//可改进量

    void init(int n){
        this->n=n;
        for(int i=0;i<n;i++)G[i].clear();
        edges.clear();
    }

    void AddEdge(int from,int to,int cap,int cost){
        edges.push_back(Edge(from,to,cap,0,cost));
        edges.push_back(Edge(to,from,0,0,-cost));
        m=edges.size();
        G[from].push_back(m-2);
        G[to].push_back(m-1);
    }

    bool BellmanFord(int s,int t,int &flow,long long &cost){
        for(int i=0;i<n;i++)d[i]=INF;
        memset(inq,0,sizeof(inq));
        d[s]=0;inq[s]=1;p[s]=0;a[s]=INF;

        queue<int>Q;
        Q.push(s);
        while(!Q.empty()){
            int u=Q.front();Q.pop();
            inq[u]=0;
            for(int i=0;i<G[u].size();i++){
                Edge &e=edges[G[u][i]];
                if(e.cap>e.flow&&d[e.to]>d[u]+e.cost){
                    d[e.to]=d[u]+e.cost;
                    p[e.to]=G[u][i];
                    a[e.to]=min(a[u],e.cap-e.flow);
                    if(!inq[e.to]){Q.push(e.to);inq[e.to]=1;}
                }
            }
        }
        if(d[t]==INF)return false;
        flow+=a[t];
        cost+=(long long)d[t]*(long long)a[t];
        for(int u=t;u!=s;u=edges[p[u]].from){
            edges[p[u]].flow+=a[t];
            edges[p[u]^1].flow-=a[t];
        }
        return true;
    }

    //需要保证初始网络中没有负权圈
    int MincostMaxflow(int s,int t,long long &cost){
        int flow=0;cost=0;
        while(BellmanFord(s,t,flow,cost));
        return flow;
    }
};

int main(){
    return 0;
}
View Code

c2.SPFA版费用流

/*
SPFA版费用流
最小费用最大流,求最大费用最大流只需要取相反数,结果取相反数即可。
点的总数为N,点的编号0~N-1
*/
#include<iostream>
#include<stdio.h>
#include<string.h>
#include<queue>
using namespace std;

const int MAXN=10000;
const int MAXM=100000;
const int INF=0x3f3f3f3f;
struct Edge{
    int to,next,cap,flow,cost;
}edge[MAXM];
int head[MAXN],tol;
int pre[MAXN],dis[MAXN];
bool vis[MAXN];
int N;//节点总个数,节点编号从0~N-1
void init(int n){
    N=n;
    tol=0;
    memset(head,-1,sizeof(head));
}
void addedge(int u,int v,int cap,int cost){
    edge[tol].to=v;
    edge[tol].cap=cap;
    edge[tol].cost=cost;
    edge[tol].flow=0;
    edge[tol].next=head[u];
    head[u]=tol++;
    edge[tol].to=u;
    edge[tol].cap=0;
    edge[tol].cost=-cost;
    edge[tol].flow=0;
    edge[tol].next=head[v];
    head[v]=tol++;
}
bool spfa(int s,int t){
    queue<int>q;
    for(int i=0;i<N;i++){
        dis[i]=INF;
        vis[i]=false;
        pre[i]=-1;
    }
    dis[s]=0;
    vis[s]=true;
    q.push(s);
    while(!q.empty()){
        int u=q.front();
        q.pop();
        vis[u]=false;
        for(int i=head[u];i!=-1;i=edge[i].next){
            int v=edge[i].to;
            if(edge[i].cap>edge[i].flow&&dis[v]>dis[u]+edge[i].cost){
                dis[v]=dis[u]+edge[i].cost;
                pre[v]=i;
                if(!vis[v]){
                    vis[v]=true;
                    q.push(v);
                }
            }
        }
    }
    if(pre[t]==-1)return false;
    else return true;
}
//返回的是最大流,cost存的是最小费用
int minCostMaxflow(int s,int t,int &cost){
    int flow=0;
    cost=0;
    while(spfa(s,t)){
        int Min=INF;
        for(int i=pre[t];i!=-1;i=pre[edge[i^1].to]){
            if(Min>edge[i].cap-edge[i].flow)
                Min=edge[i].cap-edge[i].flow;
        }
        for(int i=pre[t];i!=-1;i=pre[edge[i^1].to]){
            edge[i].flow+=Min;
            edge[i^1].flow-=Min;
            cost+=edge[i].cost*Min;
        }
        flow+=Min;
    }
    return flow;
}

int main(){
    return 0;
}
View Code

c3.zkw费用流

/*
zkw费用流
对于二分图类型的比较高效
*/
#include<iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

const int MAXN=100;
const int MAXM=20000;
const int INF=0x3f3f3f3f;
struct Edge{
    int to,next,cap,flow,cost;
    Edge(int _to=0,int _next=0,int _cap=0,int _flow=0,int _cost=0):
        to(_to),next(_next),cap(_cap),flow(_flow),cost(_cost){}
}edge[MAXM];
struct ZKW_MinCostMaxFlow{
    int head[MAXN],tot;
    int cur[MAXN];
    int dis[MAXN];
    bool vis[MAXN];
    int ss,tt,N;//源点、汇点和点的总个数(编号是0~N-1),不需要额外赋值,调用会直接赋值
    int min_cost,max_flow;
    void init(){
        tot=0;
        memset(head,-1,sizeof(head));
    }
    void addedge(int u,int v,int cap,int cost){
        edge[tot]=Edge(v,head[u],cap,0,cost);
        head[u]=tot++;
        edge[tot]=Edge(u,head[v],0,0,-cost);
        head[v]=tot++;
    }
    int aug(int u,int flow){
        if(u==tt)return flow;
        vis[u]=true;
        for(int i=cur[u];i!=-1;i=edge[i].next){
            int v=edge[i].to;
            if(edge[i].cap>edge[i].flow&&!vis[v]&&dis[u]==dis[v]+edge[i].cost){
                int tmp=aug(v,min(flow,edge[i].cap-edge[i].flow));
                edge[i].flow+=tmp;
                edge[i^1].flow-=tmp;
                cur[u]=i;
                if(tmp)return tmp;
            }
        }
        return 0;
    }
    bool modify_label(){
        int d=INF;
        for(int u=0;u<N;u++)
            if(vis[u])
                for(int i=head[u];i!=-1;i=edge[i].next){
                    int v=edge[i].to;
                    if(edge[i].cap>edge[i].flow&&!vis[v])
                        d=min(d,dis[v]+edge[i].cost-dis[u]);
                }
        if(d==INF)return false;
        for(int i=0;i<N;i++)
            if(vis[i]){
                vis[i]=false;
                dis[i]+=d;
            }
        return true;
    }
    /*
    直接调用获取最小费用和最大流
    输入:start-源点,end-汇点,n-点的总个数(编号从0开始)
    返回值:pair<int,int>第一个是最小费用,第二个是最大流
    */
    pair<int,int> mincostmaxflow(int start,int end,int n){
        ss=start,tt=end,N=n;
        min_cost=max_flow=0;
        for(int i=0;i<n;i++)dis[i]=0;
        while(1){
            for(int i=0;i<n;i++)cur[i]=head[i];
            while(1){
                for(int i=0;i<n;i++)vis[i]=false;
                int tmp=aug(ss,INF);
                if(tmp==0)break;
                max_flow+=tmp;
                min_cost+=tmp*dis[ss];
            }
            if(!modify_label())break;
        }
        return make_pair(min_cost,max_flow);
    }
}solve;

int main(){
    return 0;
}
View Code

c4.这哥们的代码效率挺高,也挺清晰。可以参考。

山东省第三届省赛 C 题 – An interesting game(费用流)

原文地址:https://www.cnblogs.com/gongpixin/p/5365242.html