用php写的一个猜数字的程序

写一个php的猜数字的小程序，提高自己对php的熟悉程度。

 1 <?php
 2 $count=rand(0,100);
 3 $number = (isset($_POST['number'])) ? $_POST['number']:$count;
 4 
 5 if(!isset($_POST['guess'])){
 6  $message =  "please enter a number";
 7 }
 8 elseif(!is_numeric($_POST['guess'])){
 9  $message = "please make sure you entered a number";
10 }
11 elseif($_POST['guess'] > $number){
12  $message = "too big";
13 }
14 elseif($_POST['guess'] < $number){
15  $message = "too small";
16 }
17 else if($_POST['guess'] == $number){
18  header("Location:success.php");
19 }
20 else{
21  $message = "so confused";
22 }
23 ?>
24 
25 <!doctype html>
26 <html>
27 <head>
28  <title>A number guess game</title>
29  <meta charset="UTF-8">
30  <title>Document</title>
31 </head>
32 <body>
33 <h1><?php echo $number?></h1>
34 <h1><?php echo $message?></h1>
35 <form action = "<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
36  <p><label for="guess">Type your answer</label> </p>
37  <input type="text" id="guess" name="guess"/>
38  <input type="hidden" name="number" value = "<?php echo $number?>" >
39  <button type="submit" name="submit" value="submit">Submit</button>
40 </form>
41 </body>
42 </html>

总结：

1.第2行代码：$number = (isset($_POST['number'])) ? $_POST['number']:$count; 这样写可以保证每次刷新页面时答案不会变化；

2.第18行代码：header("Location:success.php");转去success.php页面；

3.第35行代码: action = "<?php echo $_SERVER['PHP_SELF']; ?>"；传回本页面；

4.第38行代码：<input type="hidden" name="number" value = "<?php echo $number?>" > 不在页面显示而传值；

5.（不在本项目中）:<?php phpinfo(); ?>输出PHP的安装信息