bash 实现菜单

#!/bin/bash
a=`ls /data1/chenggang5/kepler/cases`
cat <<EOF
`j=0;for i in $a;do let j=$j+1;if [ $((j%5)) -ne 0 ];then print=\`printf "%-21s	" $i\`;echo -n -e "e[1;32m $print e[0m";else print=\`printf "%-21s" $i\`;echo -e "e[1;32m $print e[0m";fi; done`
EOF
while [ 0 ] 
do
echo -n -e "e[1;33m【请选择要执行的案例,如输入03,输入all,则执行全部案例,输入q或e,则退出程序】:e[0m"
read input
for i in $a
do
w=`echo $i|awk -F. '{print $1}'`
x=`echo $i|awk -F. '{print $0}'`
case $input in
  $w)
  sh ../bin/run.sh cases/$x
esac
done
case $input in
  all)
  sh ../bin/run.sh cases
  ;;
  q)
  exit;;
  Q)
  exit;;
  e)
  exit;;
  E)
  exit;;
esac
done

  命令详解:

cat <<EOF

EOF

控制多行输出

`j=0;for i in $a;do let j=$j+1;if [ $((j%5)) -ne 0 ];then print=\`printf "%-21s	" $i\`;echo -n -e "e[1;32m $print e[0m";else print=\`printf "%-21s" $i\`;echo -e "e[1;32m $print e[0m";fi; done`
这一行主要是 规定每行的输出列数,并对其进行颜色设置

while [ 0 ] 控制循环;read 读取键盘输入;case 进行选择
效果图如下:


原文地址:https://www.cnblogs.com/ggbond1988/p/4835078.html