冒泡排序。去重练习

冒泡排序:

var arr = [9, 8, 7, 6, 2, 1, 3, 5, 4]

for(n = 0; n < arr.length; n++) {

    for(var m = n + 1; m < arr.length; m++){

         if(arr[n] > arr[m]) {

            var temp = arr[n]; arr[n] = arr[m]; arr[m] = temp

              }

         }

}

document.write(arr)

去重:

var arr1=[1,1,2,2,3,3,4,4,5,5]

var arr2=[ ]

for(var m=0; m<arr1.length; m++){

var a=0 for(var n=0; n<arr2.length; n++){

if(arr1[m]==arr2[n])

{ a=1 }

}

if(a==0){

arr2.push(arr1[m]) }

}

alert(arr2)

原文地址:https://www.cnblogs.com/gbbwzz/p/7589410.html