js 一个或多个一维数组,算出元素之间相互组合的所有情况

// 数据源
    var target = {
        state1: ['1', '2'],
        state2: ['01', '02', '03'],
        state3: ['001','002']
    }
    
    stackSituation(target)

    function stackSituation (data) {
        var targetKeys = Object.keys(data)
        var target = faker = []
        if (targetKeys.length) {
            target = targetKeys.map((key) => data[key])
            faker = target[0]
        }

        target.forEach((itemArr, index, currentArr) => {
            faker = js(faker, currentArr[index + 1])
        })
        function js(arr1, arr2){
            var arr1 = arr1 || []
            var arr2 = arr2 || []
            faker = []
            for(var i = 0;i < arr1.length; i++){
                if (!arr2.length) {
                    faker.push(arr1[i])
                } else {
                    for(var j = 0; j < arr2.length; j++){                     
                        faker.push(arr1[i] + '_' +arr2[j]);
                     }
                }
            }
            return faker
        }
        var result = faker.map((item) => item.split('_'))
        console.table(result)
        return result
    }
原文地址:https://www.cnblogs.com/gavin007/p/7920649.html