【leetcode】40. 组合总和 II

int cmp(const void* a,const void* b){
    return *(int*)a-*(int*)b;
}
void recursion(int* candidates,int candidatesSize,int** arr,int* temp,int pst,int target,int res,int* returnSize,int* returnColumnSizes,int start){    
    for(int i=start; i<candidatesSize && res<target; i++){
        temp[pst]=candidates[i];
        if(res+candidates[i] >= target){
            if(res+candidates[i]==target){
                arr[(*returnSize)]=(int*)calloc(pst+1,sizeof(int));
                memcpy(arr[(*returnSize)],temp,++pst*sizeof(int));
                returnColumnSizes[(*returnSize)]=pst;
                (*returnSize)++;
            }
            break;        
        }            
        recursion(candidates,candidatesSize,arr,temp,pst+1,target,res+candidates[i],returnSize,returnColumnSizes, i+1);
        while(i!=candidatesSize-1 && candidates[i]==candidates[i+1])
            i++;
        temp[pst]=0;
    }
}

int** combinationSum2(int* candidates, int candidatesSize, int target, int* returnSize, int** returnColumnSizes){
    int** arr=(int**)calloc(1000,sizeof(int*));
    *returnColumnSizes=(int*)calloc(1000,sizeof(int));
    *returnSize=0;
    int temp[1000]={0};
    qsort(candidates,candidatesSize,sizeof(int),cmp);
    recursion(candidates,candidatesSize,arr,temp,0,target,0,returnSize,*returnColumnSizes,0);
    return arr;
}
原文地址:https://www.cnblogs.com/ganxiang/p/14107517.html