【leetcode】108. 将有序数组转换为二叉搜索树

struct TreeNode* sortedArrayToBST(int* nums, int numsSize){
     struct TreeNode* p_node=(struct TreeNode*)malloc(sizeof(struct TreeNode));
     if(0==numsSize || NULL==nums) return NULL;
     int mid=numsSize/2;
     p_node->val=nums[mid];
     p_node->left=sortedArrayToBST(nums,mid);
     p_node->right=sortedArrayToBST(&nums[mid+1],numsSize-mid-1);
     return p_node;
}
原文地址:https://www.cnblogs.com/ganxiang/p/14036019.html