【leetcode】696. 计数二进制子串

#define min(a,b) (a<b)?(a) :(b)
int countBinarySubstrings(char * s){
    int i, j, cnt = 0, len = strlen(s), sum=0, preVal=0, ret;
    for (i = 0; i < len; i++){
        cnt++;
        if (i == len-1 || s[i] != s[i + 1]){
            sum += min(cnt, preVal);
            preVal = cnt;
            cnt = 0;
        }
    }
    return sum;
}
原文地址:https://www.cnblogs.com/ganxiang/p/14032364.html