【leetcode】找出井字棋的获胜者

char * tictactoe(int** moves, int movesSize, int* movesColSize){
    int hash[2][8]={0},i;
    char* s[] = {"A","B"};
    for (i=0; i<movesSize; i++)
    {
        //累计行子
        hash[i%2][moves[i][0]]++;
        //累计列子
        hash[i%2][moves[i][1]+3]++;
        //累计主对角线
        if (moves[i][0] == moves[i][1])
            hash[i%2][6]++;
        //累计副对角线
        if (moves[i][0] + moves[i][1] == 2)
            hash[i%2][7]++;
        if (hash[i%2][moves[i][0]]==3 || hash[i%2][moves[i][1]+3]==3 || hash[i%2][6]==3 || hash[i%2][7]==3)
            return s[i%2];
    }
    return (i==9)? "Draw": "Pending";
}