【leetcode】逐步求和得到正数的最小值

int minStartValue(int* nums, int numsSize){
    int min=0,sum=0;
    for (int i=0; i<numsSize; i++)
    {
        sum += nums[i];
        if (sum < min) min = sum;
    }
    return (1-min <=1)? 1: 1-min;
}
原文地址:https://www.cnblogs.com/ganxiang/p/13680377.html