【leetcode】0~n1中缺失的数字

int missingNumber(int* nums, int numsSize){
    for (int i=0; i<numsSize; i++)
    {
        if (nums[i]!=i)
            return i;
    }
    return numsSize;
}
原文地址:https://www.cnblogs.com/ganxiang/p/13511530.html