bzoj1058 [ZJOI2007]报表统计

传送门：http://www.lydsy.com/JudgeOnline/problem.php?id=1058

【题解】

这个insert操作好py啊是不是用set就能搞搞啊。

什么？你跟我讲T了？

读入优化？还是T？

卡了卡常，发现一个东西用priority_queue就够了。。

然后12s过了。

# include <set>
# include <queue>
# include <stdio.h>
# include <string.h>
# include <iostream>
# include <algorithm>
// # include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
const int M = 5e5 + 10;
const int mod = 1e9+7;

# define RG register
# define ST static

int n, q, a[M];
int beg[M], end[M]; 

multiset<int> num;
multiset<int> st2;
priority_queue<int, vector<int>, greater<int> > st1;

inline int read() {
    int x = 0, f = 1; 
    char ch = getchar();
    while(!isdigit(ch)) {
        if(ch == '-') f = -1;
        ch = getchar();
    }
    while(isdigit(ch)) {
        x = (x<<3)+(x<<1)+ch-'0';
        ch = getchar();
    }
    return x*f;
}

inline void del(int x) {
    st2.erase(st2.find(x));
}

multiset<int>::iterator it;

inline void push(int x) {
    int ins = 1e9;
    it = num.lower_bound(x);
    if(it != num.end()) {
        int y = *it;
        ins = min(ins, y-x);
    }
    if(it != num.begin()) {
        int y = *--it;
        ins = min(ins, x-y);
    }
    st1.push(ins);
    num.insert(x);
}
int main() {
    cin >> n >> q;
    for (int i=1, t; i<=n; ++i) {
//        printf("i = %d
", i);
        t = read();
        beg[i] = end[i] = t;
        push(t);
        if(i >= 2) st2.insert(abs(t - beg[i-1]));
    }
    char st[23];
    int ps, d;
    while(q--) {
        scanf("%s", st);
        if(st[0] == 'I') {
            ps = read(), d = read();
            push(d);
            if(ps != n) {
                del(abs(end[ps] - beg[ps+1]));
                st2.insert(abs(d - end[ps]));
                st2.insert(abs(d - beg[ps+1]));
            } else st2.insert(abs(d - end[ps]));
            end[ps] = d;
        } else if(st[4] == 'S') printf("%d
", st1.top());
        else printf("%d
", *st2.begin());
    }
    return 0;
}