9.最长公共子序列

 

时间复杂度n^2

debug过程

 

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 const int N = 1010;
 4 char a[N], b[N];
 5 int dp[N][N];
 6 int main() {
 7     int n, m;
 8     cin >> n >> m;
 9     cin >> a + 1 >> b + 1;
10     for (int i = 1; i <= n; i++) {
11         for (int j = 1; j <= m ; j++) {
12             dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);
13             if (a[i] == b[j]) {
14                 dp[i][j] = max(dp[i][j], dp[i - 1][j - 1] + 1);
15             }
16         }
17     }
18     cout << dp[n][m] << endl;
19     return 0;
20 }
原文地址:https://www.cnblogs.com/fx1998/p/12836315.html