sqlserver 根据经纬度计算两点之间距离

计算函数:
–计算地球上两个坐标点(经度,纬度)之间距离sql函数 –作者:lordbaby –整理:www.aspbc.com
CREATE FUNCTION [dbo].[fnGetDistance](@LatBegin REAL, @LngBegin REAL, @LatEnd REAL, @LngEnd REAL)
RETURNS FLOAT
AS
BEGIN
–距离(千米)
DECLARE @Distance REAL
DECLARE @EARTH_RADIUS REAL
SET @EARTH_RADIUS = 6378.137
DECLARE @RadLatBegin REAL,@RadLatEnd REAL,@RadLatDiff REAL,@RadLngDiff REAL
SET @RadLatBegin = @LatBegin *PI()/180.0
SET @RadLatEnd = @LatEnd *PI()/180.0
SET @RadLatDiff = @RadLatBegin - @RadLatEnd
SET @RadLngDiff = @LngBegin *PI()/180.0 - @LngEnd *PI()/180.0
SET @Distance = 2 *ASIN(SQRT(POWER(SIN(@RadLatDiff/2), 2)+COS(@RadLatBegin)*COS(@RadLatEnd)*POWER(SIN(@RadLngDiff/2), 2)))
SET @Distance = @Distance * @EARTH_RADIUS
–SET @Distance = Round(@Distance * 10000) / 10000
RETURN @Distance
END

使用方法如下:

SELECT * FROM 表名 WHERE dbo.fnGetDistance(108.89382764697076,34.16389439109832,longitude,latitude) < 5
————————————————
版权声明:本文为CSDN博主「Ms___」的原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接及本声明。
原文链接:https://blog.csdn.net/Ms___/article/details/78780705

原文地址:https://www.cnblogs.com/future/p/12517746.html