简单排序

题目要求

代码块

#include <stdio.h>
int main() {
	int n;
	int buf[100];
	while (scanf("%d", &n) != EOF) {

		for (int i = 0; i < n; i++) {
			scanf("%d", &buf[i]);
		}
	
		//冒泡排序主体
		for (int i = 0; i < n - 1; i++)
		{
			for (int j = 0; j < n-i-1; j++)
			{
				if (buf[j] > buf[j+1])
				{
					int tmp = buf[j + 1];
					buf[j + 1] = buf[j];
					buf[j] = tmp;
				}
			}
		}

		//输出数组
		for (int i = 0; i < n; i++)
		{
			printf("%d ", buf[i]);
		}
		printf("
");
	}
	return 0;
}
原文地址:https://www.cnblogs.com/forfly/p/8531411.html