Newtonsoft.Json的初步用法

建立一个json对象并转化为字符输出

输出结果:

{
  "属性1": "内容1",
  "Data": [
    ["a1","b1","c1","d1"],
    ["a2","b2","c2","d2"],
    ["a3","b3","c3","d3"]
  ]
}

C#代码:

 1 JObject jobj = new JObject();
 2 
 3 jobj.Add("属性1", "内容1");
 4 
 5 JArray dataArr = new JArray();
 6 dataArr.Add(new JArray(new string[] { "a1", "b1", "c1", "d1" }));
 7 dataArr.Add(new JArray(new string[] { "a2", "b2", "c2", "d2" }));
 8 dataArr.Add(new JArray(new string[] { "a3", "b3", "c3", "d3" }));
 9 jobj.Add("Data", dataArr);
10 
11 Response.Write();
12 Response.End();
原文地址:https://www.cnblogs.com/foreveryu/p/4595718.html