HDU 1850 Being a Good Boy in Spring Festival

题解:尼姆博弈,SG(i)=i,要使当前堆可取,则数量必须大于其余所有堆的SG异或值,这样才可以减到其SG值使总异或值为0,又不可不取,所以不能取等号。

#include <cstdio>    
using namespace std;    
int SG[105];    
int main(){    
    int n,sum,cnt,i;    
    while (scanf("%d",&n),n){    
        sum=cnt=0;    
        for(i=0;i<n;i++)scanf("%d",&SG[i]),sum^=SG[i];       
        for(i=0;i<n;i++){sum^=SG[i];if(SG[i]>sum)cnt++;sum^=SG[i];}    
        printf("%d
",cnt);    
    }    
    return 0;    
}  
原文地址:https://www.cnblogs.com/forever97/p/3676483.html