HDU 1002 A + B Problem II

/*高精度*/
#include <cstdio>
#include <iostream>
using namespace std;
const int modnum=10;
int main()
{
    int n;
    scanf("%d",&n);
    int m=n;
    while(n--)
    {
        printf("Case %d:
",m-n);
        int a[1010]={0},b[1010]={0},c[1010]={0};
        char ch1[1010],ch2[1010];
        scanf("%s",&ch1);
        scanf("%s",&ch2);
        a[0]=strlen(ch1);
        for (int i=1; i<=a[0]; i++)
        a[i]=ch1[a[0]-i]-'0';
        b[0]=strlen(ch2);
        for (int i=1; i<=b[0]; i++)
        b[i]=ch2[b[0]-i]-'0';
        int x=0,i=0;
        c[0]=a[0]>b[0]?a[0]:b[0];
        for (int i=1;i<=c[0];i++) c[i]=a[i]+b[i];
        for (int i=1;i<=c[0];i++){
            c[i+1]+=c[i]/modnum;
            c[i]%=modnum;
        }
        c[0]++;
        while ((c[0] > 1) && (c[c[0]] == 0)) c[0]--;
        for (int i=a[0]; i; i--) printf("%d",a[i]);
        printf(" + ");
        for (int i=b[0]; i; i--) printf("%d",b[i]);
        printf(" = ");
        for (int i=c[0]; i; i--) printf("%d",c[i]);
        printf("
");
        if (n) printf("
");
    }  
    return 0;
}