18. 4Sum

description:

Given an array nums of n integers and an integer target, are there elements a, b, c, and d in nums such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target.

Note:
The solution set must not contain duplicate quadruplets.
Example:

Given array nums = [1, 0, -1, 0, -2, 2], and target = 0.

A solution set is:
[
  [-1,  0, 0, 1],
  [-2, -1, 1, 2],
  [-2,  0, 0, 2]
]

my answer:

感恩

my answer

思路和上一道题3sum是一样的，就是多加了个for循环，先后固定两个数，再找另外两个数

大佬的answer：

class Solution {
public:
    vector<vector<int>> fourSum(vector<int> &nums, int target) {
        set<vector<int>> res;
        sort(nums.begin(), nums.end());
        for (int i = 0; i < int(nums.size() - 3); ++i) {
            for (int j = i + 1; j < int(nums.size() - 2); ++j) {
                if (j > i + 1 && nums[j] == nums[j - 1]) continue;
                int left = j + 1, right = nums.size() - 1;
                while (left < right) {
                    int sum = nums[i] + nums[j] + nums[left] + nums[right];
                    if (sum == target) {
                        vector<int> out{nums[i], nums[j], nums[left], nums[right]};
                        res.insert(out);//这里要用insert， 因为res是个set
                        ++left; --right;
                    } else if (sum < target) ++left;
                    else --right;
                }
            }
        }
        return vector<vector<int>>(res.begin(), res.end());//因为res是set，所以不能直接返回，要处理一下
    }
};

relative point get√：

hint :