是用VLC API将RTSP流convert为视频文件

一直在文档中找不到，接口设计的也不大好。不过终于在stackoverflow上找到解决方案了。

原来在LIbVLC库实例化的时候就需要传递相关的参数。我的代码大致是这样实现：

 1 const char * vlc_args[] =
 2     {
 3         "--sout="
 4     };
 5 
 6     if ((m_vlcInsatnce = libvlc_new(sizeof(vlc_args)/sizeof(vlc_args[0]), vlc_args)) == NULL)
 7     {
 8         std::cerr << "Could not init VLC" << std::endl;
 9         exit(1);
10     }
11 
12 
13 //开始录制转换
14 QString sout = "#transcode{vcodec=mp4v,acodec=mpga,vb=800,ab=128,deinterlace}:duplicate{dst=file{dst=" + m_recordFile + "}}";
15                 
16                 
17                 libvlc_vlm_add_broadcast(m_vlcInsatnce, media_name, m_url.toStdString().c_str(), sout.toStdString().c_str(), 0, NULL, true, true);
18                 libvlc_vlm_play_media(m_vlcInsatnce, media_name);
19 
20 //这里可以加入一些时间，录制时间
21 //停止录制
22 libvlc_vlm_stop_media(m_vlcInsatnce, media_name);
23             libvlc_vlm_del_media(m_vlcInsatnce, media_name);
24 
25             libvlc_vlm_release(m_vlcInsatnce);

View Code

详情可以参考我的Github上一个媒体播放器的代码：

https://github.com/AlexiaChen/MediaPlayer

references：

http://stackoverflow.com/questions/16515099/saving-a-stream-while-playing-it-using-libvlc

http://stackoverflow.com/questions/26464138/how-to-stream-raw-data-from-memory-using-libvlc-and-visual-studio-2008?rq=1

http://blog.csdn.net/xuplus/article/details/34081989