laravel 查询数据toArray内层无法转换的问题

语法:get_object_var($object),返回一个数组。获取$object对象中的属性,组成一个数组

<?php
class person{
 public $name="王美人";
 public $age = 25;
 public $birth;
}
$p = new person();
print_r(get_object_vars($p));
?>

输出结果:

Array ( [name] => 王美人 [age] => 25 [birth] => )

在laravel数据库查询中使用toArray()方法外层已经转化成了数组,但是内层依然是对象的问题。

array (size=1)
  0 => 
    object(stdClass)[1804]
      public 'id' => int 17
      public 'ip' => string '192.168.0.60' (length=12)
      public 'access_time' => int 1615625654
      public 'access_count' => int 1
      public 'last_time' => int 1615625672

  

在vendorlaravelframeworksrcIlluminateSupportCollection.php中增加方法 getArrayList()

 public function toArray()
    {
        return array_map(function ($value) {
            return $value instanceof Arrayable ? $value->toArray() : $value;
        }, $this->items);
    }
/*增加方法*/
    public function getArrayList(){
        return array_map('get_object_vars', $this->items);

    }

查询时使用:

DB::table('api_log')->select('id','ip','access_time','access_count','last_time')->where('ip',$logInfo['ip'])->orderBy('id','desc')->limit(1)->get()->getArrayList()[0];

显示结果:

array (size=5)
  'id' => int 17
  'ip' => string '192.168.0.60' (length=12)
  'access_time' => int 1615625654
  'access_count' => int 0
  'last_time' => int 1615625654

  

Array ( [name] => 王美人 [age] => 25 [birth] => )

原文地址:https://www.cnblogs.com/fogwang/p/14529578.html