C语言实现进制转换

#include<stdio.h>
int main()
{
    char ku[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
    int zh[32],i=0,w,j;
    long int b,y;
    printf("请输入一个十进制数,我能帮您把它转换成2~16任意进制数: ");
    scanf("%d",&y);
    b=y;
    printf("请输入要转换为的进制:");
    scanf("%d",&w);
    printf(" ");
    do
    {
        zh[i]=y%w;
        i++;
        y=y/w;
    }
    while(y!=0);
    printf("把十进制的%ld转换为%d进制:",b,w);
    for(i--;i>=0;i--)
    {
        j=zh[i];
        printf("%c",ku[j]);
    }
    printf(" ");
    return 0;
}
原文地址:https://www.cnblogs.com/flypie/p/4628630.html