python-读取excel文件

# -*- coding:utf-8 -*-

__author__ = 'zzd'
import xlrd
#open excelfile
def open_excel(file):
    try:
        data = xlrd.open_workbook(file)
        return data
    except Exception,e:
        print(str(e))
#根据名称获取Excel表格中的数据   参数:file:Excel文件路径  by_name:Sheet1名称
def excel_table_byname(data,by_name):
    # table = data.sheet_by_name(unicode(by_name, "utf-8"))
    table = data.sheet_by_name(by_name.encode('gbk'))
    nrows = table.nrows #行数
    ncols = table.ncols # 列数
    list =[[] for i in range(nrows)]
    for i in range(0,nrows):
        for j in range(0,ncols):
            cell = table.cell(i,j).value
            if(cell!=""):
                list[i].append(cell)
    return list
# get table's index info from sheet 1
def getTbInfo(data):
    dataList = excel_table_byname(data,"Sheet1")
    for i in range(len(dataList[0])):
        if(dataList[0][i]==u'表名'):
            index=i
    # print index
    tbinfos={}
    #i代表表格的行,j代表表格的列
    for i in range(2,len(dataList)):
        tbinfo={}
        tbname=dataList[i][index]
        # print len(dataList[i])
        for j in range(len(dataList[0])):
            key=dataList[0][j].strip()
            if(j<len(dataList[i])):
                value=dataList[i][j]
            else:
                value=""
            tbinfo[key]=value
        tbinfos[tbname]=tbinfo
    return tbinfos
原文地址:https://www.cnblogs.com/fengzzi/p/10042836.html