codeforces 6C Alice, Bob and Chocolate

从两端模拟向中间靠拢

#include <stdlib.h>

#include <string.h>
#include <stdio.h>
#include <ctype.h>
#include <math.h>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <vector>
#include <string>
#include <iostream>
#include <algorithm>
using namespace std;
#define ll long long
#define ls rt<<1
#define rs ls1
#define lson l,mid,ls
#define rson mid+1,r,rs
#define middle (l+r)>>1
#define eps (1e-9)
#define clr_all(x,c) memset(x,c,sizeof(x))
#define clr(x,c,n) memset(x,c,sizeof(x[0])*(n+1))
#define MOD 1000000007
#define inf 100000007
#define pi acos(-1.0)
#define M 100000+5
int r[M];
int main(){
    int n,i,j,ca,cb;
    while(~scanf("%d",&n)){
for(i=0;i<n;i++)scanf("%d",&r[i]);
i=0,j=n-1;ca=cb=0;
while(i<=j){
if(i==j&&ca==cb){
ca+=r[i++];
break;
}
if(ca<cb)ca+=r[i++];
else if(ca>cb)cb+=r[j--];
else ca+=r[i++],cb+=r[j--];
}
printf("%d %d\n",i,n-i);
}
    return 0;
}

每天进步一点,永不停止
原文地址:https://www.cnblogs.com/fanzhongrui/p/3118248.html