循环程序练习

public class fenzhi {

    public static void main(String[] args) 
    {
        // 求一百以内奇数
        
        int n = 100;
        
        int a = -1;
        
        for (int b = 1;b <= n; b++)
        
            {
              a = a + 2;      
            
              if (a >= n)
                    
                    break;
              
              System.out.println(a);
                
            }
                
            //求一百以内与7相关的数
        int l = 100;
        
        for (a = 1; a < l; a++)
        {
            if((a % 7) == 0)//被7整除
                System.out.println("a =" + a);
            
            else if((a % 10) == 7)//个位数是7
                System.out.println("a =" + a);
            
            else if ((a / 7) == 10  )//十位数是7
            System.out.println("a =" + a);
            
            else if((a == 78) || (a == 79))
                System.out.println("a =" + a);    
            
        }
        //百鸡百钱:现有公鸡2钱一只,母鸡1钱一只,小鸡半钱一只;现有100钱。
        //问;购买不超过100只鸡的所有情况
        
       //设:公鸡=i  母鸡=q  小鸡=k
        int t = 100;
        
        for(int i = 0;i <=50; i++ )
        {
            for(int q = 0;q <=(t-i); q++)
            {
                for(int k = 0;k <=(t-i-q); k++)
                {
                if    ((q + 2*i +0.5*k) <= t) //购买不超过100只鸡所需钱数
                    System.out.println("i =" + i + "q =" + q + "k =" + k);
                    
                }
            }
        }
        
        
        
        
        
        
        
        
        
        
    }

}
原文地址:https://www.cnblogs.com/fangchongyan/p/5020979.html