写了半场考试你告我正解是bitset？？而且竟然比我跑得快？？
1 #include<iostream> 2 #include<cstdio> 3 #include<algorithm> 4 #include<cstring> 5 #include<vector> 6 #define inf 0x3f3f3f3f 7 #define N 50005 8 #define ls a[x].l,a[y].l,l,mid 9 #define rs a[x].r,a[y].r,mid+1,r 10 using namespace std; 11 int n; 12 const int mx=50000; 13 inline int read() 14 { 15 char c=getchar();int p=0,f=1; 16 while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();} 17 while(c>='0'&&c<='9')p=p*10+c-'0',c=getchar(); 18 return p*f; 19 } 20 struct fk 21 { 22 struct point 23 { 24 int x,y; 25 friend bool operator < (const point &aa,const point &bb) 26 { 27 if(aa.y!=bb.y)return aa.y<bb.y; 28 return aa.x<bb.x; 29 } 30 }dian[N]; 31 int lix[N+5],liy[N+5],cnt1,cnt2,pre[mx+5],now[mx+5]; 32 struct node 33 { 34 int l,r,sum; 35 }a[N*350];int cnt; 36 int qur(int x,int y,int l,int r,int ll,int rr) 37 { 38 if(l>=ll&&r<=rr)return a[x].sum-a[y].sum; 39 int mid=(l+r)>>1; 40 if(ll>mid)return qur(rs,ll,rr); 41 if(rr<=mid)return qur(ls,ll,rr); 42 return qur(ls,ll,rr)+qur(rs,ll,rr); 43 } 44 void insert(int x,int y,int l,int r,int pos) 45 { 46 if(l==r) 47 { 48 a[x].sum=a[y].sum+1; 49 return ; 50 } 51 int mid=(l+r)>>1; 52 if(pos<=mid) 53 { 54 if(!a[x].l)a[x].l=++cnt; 55 a[x].r=a[y].r; 56 insert(ls,pos); 57 } 58 else 59 { 60 if(!a[x].r)a[x].r=++cnt; 61 a[x].l=a[y].l; 62 insert(rs,pos); 63 } 64 a[x].sum=a[a[x].l].sum+a[a[x].r].sum; 65 return ; 66 } 67 vector<int>root[N*3],xx[N*3]; 68 vector<int>::iterator it; 69 struct nd 70 { 71 int pr,yuan; 72 nd(int x,int y) 73 { 74 yuan=x;pr=y; 75 } 76 friend bool operator < (const nd &aa,const nd &bb) 77 { 78 return aa.pr<bb.pr; 79 } 80 }; 81 vector<nd>pai[N*3]; 82 void jia(int x) 83 { 84 int pr=-1,prroot=0; 85 root[x].push_back(0);xx[x].push_back(-1); 86 for(int i=0;i<pai[x].size();i++) 87 { 88 int pp=pai[x][i].yuan; 89 if(pre[pp]==pr) 90 { 91 root[x][root[x].size()-1]=++cnt; 92 insert(root[x][root[x].size()-1],prroot,0,mx,dian[pp].x); 93 } 94 else 95 { 96 root[x].push_back(++cnt); 97 xx[x].push_back(pre[pp]); 98 insert(root[x][root[x].size()-1],prroot,0,mx,dian[pp].x); 99 } 100 pr=pre[pp]; 101 prroot=root[x][root[x].size()-1]; 102 } 103 xx[x].push_back(0x3f3f3f3f); 104 return ; 105 } 106 void build(int x,int l,int r,int ll,int rr) 107 { 108 if(ll>rr)return ; 109 int mid=(l+r)>>1; 110 int ed=rr; 111 for(int i=ll;i<=rr;i++) 112 { 113 if(dian[i].y<=mid)ed=i; 114 pai[x].push_back(nd(i,pre[i])); 115 } 116 sort(pai[x].begin(),pai[x].end()); 117 jia(x); 118 if(l==r)return ; 119 build(x*2,l,mid,ll,ed); 120 build(x*2+1,mid+1,r,ed+1,rr); 121 } 122 int qu(int x,int l,int r,int ll,int rr,int qx,int qy) 123 { 124 if(ll<=l&&rr>=r) 125 { 126 int ha=0;int ta=xx[x].size()-1; 127 while(ha<=ta) 128 { 129 int mid=(ha+ta)>>1; 130 if(xx[x][mid]<ll)ha=mid+1; 131 else ta=mid-1; 132 } 133 return qur(root[x][ta],0,0,mx,qx,qy); 134 } 135 int mid=(l+r)>>1; 136 if(ll>mid)return qu(x*2+1,mid+1,r,ll,rr,qx,qy); 137 if(rr<=mid)return qu(x*2,l,mid,ll,rr,qx,qy); 138 return qu(x*2+1,mid+1,r,ll,rr,qx,qy)+qu(x*2,l,mid,ll,rr,qx,qy); 139 } 140 int que(int x1,int y1,int x2,int y2) 141 { 142 if(y1>liy[cnt2]||x1>lix[cnt1])return 0; 143 if(y2<liy[1]||x2<lix[1])return 0; 144 y1=lower_bound(liy+1,liy+cnt2+1,y1)-liy; 145 x1=lower_bound(lix+1,lix+cnt1+1,x1)-lix; 146 if(y2<liy[cnt2])y2=upper_bound(liy+1,liy+cnt2+1,y2)-liy-1;else y2=cnt2; 147 if(x2<lix[cnt1])x2=upper_bound(lix+1,lix+cnt1+1,x2)-lix-1;else x2=cnt1; 148 return qu(1,1,mx,y1,y2,x1,x2); 149 } 150 void srt() 151 { 152 sort(dian+1,dian+n+1); 153 for(int i=1;i<=n;i++) 154 { 155 lix[++cnt1]=dian[i].x; 156 liy[++cnt2]=dian[i].y; 157 } 158 sort(lix+1,lix+cnt1+1);sort(liy+1,liy+cnt2+1); 159 cnt1=unique(lix+1,lix+cnt1+1)-lix-1; 160 cnt2=unique(liy+1,liy+cnt2+1)-liy-1; 161 for(int i=1;i<=n;i++) 162 { 163 dian[i].x=lower_bound(lix+1,lix+cnt1+1,dian[i].x)-lix; 164 dian[i].y=lower_bound(liy+1,liy+cnt2+1,dian[i].y)-liy; 165 } 166 return ; 167 } 168 void yu() 169 { 170 for(int i=1;i<=n;i++) 171 { 172 pre[i]=now[dian[i].x]; 173 now[dian[i].x]=dian[i].y; 174 } 175 } 176 }sx,sy; 177 int on,t1,t2,t3,t4,t5; 178 int main() 179 { 180 scanf("%d",&on); 181 scanf("%d",&n); 182 for(int i=1;i<=n;i++) 183 { 184 t1=read();t2=read(); 185 sy.dian[i].x=t1;sy.dian[i].y=t2; 186 sx.dian[i].x=t2;sx.dian[i].y=t1; 187 } 188 sx.srt(); 189 sy.srt(); 190 sx.yu(); 191 sy.yu(); 192 sx.build(1,1,mx,1,n); 193 sy.build(1,1,mx,1,n); 194 int cas; 195 scanf("%d",&cas);int lax=0,lay=0; 196 while(cas--) 197 { 198 t1=read();t2=read();t3=read();t4=read(); 199 t1=t1+(lax+lay)*on; 200 t2=t2+(lax+lay)*on; 201 t3=t3+(lax+lay)*on; 202 t4=t4+(lax+lay)*on; 203 lay=sx.que(t2,t1,t4,t3); 204 lax=sy.que(t1,t2,t3,t4); 205 printf("%d %d ",lax,lay); 206 } 207 return 0; 208 }