【转】邻接矩阵非递归输出所有简单路径

原文链接:深搜(非递归)实现获取两点之间的路径

#include <stdio.h>
#include <tchar.h>
#include <stdlib.h> 
#include <iostream>  
#include <stack>  
#include <map>
#include <vector>
using namespace std; 
 
#define NotFound  -1  
#define StartNode 0  
#define EndNode 4
map<int,map<int,int> > visited;
map<int,vector<int> > ajdTable;
int isInStack[5];
 
 
//不在栈中且路径没有访问过
int getNextPoint(int point){
    vector<int>::iterator it;
    for ( it=ajdTable[point].begin() ; it != ajdTable[point].end(); it++ ){
        if ((visited[point][*it]!=1) && (isInStack[*it]!=1))
            return *it;
    }
    return NotFound;
}
 
void setNoVisted(int point){
    vector<int>::iterator it;
    for ( it=ajdTable[point].begin() ; it != ajdTable[point].end(); it++ ){
        visited[point][*it] = 0;
    }
}
 
 
void dfs_stack(int start, int end, int n){
    int s_top,n_point;  
 
    for(int i = 0;i < n; i++){   
        isInStack[i] = 0;
    }  
 
    cout<<"begin to find: " << endl;  
    stack <int> s; 
    s.push(start);
    isInStack[start] = 1;  
 
 
    while(!s.empty()){
        s_top = s.top();
 
        //是否是终点
        if (s_top == end)
        {
            cout <<"route: ";
            for(int i = 0;i < n; i++){   
                if (isInStack[i] == 1)
                {
                    cout << i << " ";
                }
            } 
            s.pop();
            isInStack[s_top] = 0;
            cout<<endl <<"pop :"<< s_top << endl; 
        }
        else
        {
            n_point = getNextPoint(s_top);
            //没有邻接点
            if (-1 == n_point)
            {
                s.pop();
                cout<<"pop :"<< s_top << endl; 
                setNoVisted(s_top);
                isInStack[s_top] = 0;
            }
            else
            {
                s.push(n_point); 
                cout<<"push:"<< n_point << endl; 
                isInStack[n_point] = 1;
                visited[s_top][n_point] = 1;
            }
        }
    }
 
}
 
//寻找从起点0到终点4的所有路径
int _tmain(int argc, _TCHAR* argv[])
{
    visited[0][1] = 0;
    visited[1][0] = 0;
    visited[0][2] = 0;
    visited[2][0] = 0;
    visited[1][4] = 0;
    visited[4][1] = 0;
    visited[3][4] = 0;
    visited[4][3] = 0;
    visited[3][2] = 0;
    visited[2][3] = 0;
    visited[0][3] = 0;
    visited[3][0] = 0;
 
    vector<int> tempvector;
   //0
    tempvector.push_back(1);
    tempvector.push_back(2);
    tempvector.push_back(3);
    ajdTable[0] = tempvector;
    tempvector.clear();
   //1
    tempvector.push_back(0);
    tempvector.push_back(4);
    ajdTable[1] = tempvector;
    tempvector.clear();
    //2
    tempvector.push_back(0);
    tempvector.push_back(3);
    ajdTable[2] = tempvector;
    tempvector.clear();
    //3
    tempvector.push_back(0);
    tempvector.push_back(2);
    tempvector.push_back(4);
    ajdTable[3] = tempvector;
    tempvector.clear();
    //4
    tempvector.push_back(1);
    tempvector.push_back(3);
    ajdTable[4] = tempvector;
    tempvector.clear();
 
    dfs_stack(StartNode, EndNode, (int)ajdTable.size());  
    return 0;
}

原文地址:https://www.cnblogs.com/exciting/p/10117402.html