laravel学习之路2: jwt集成

"tymon/jwt-auth": "^1.0@dev",
执行 composer update
'providers' => [ .... TymonJWTAuthProvidersLaravelServiceProvider::class, // 上文已经提到过,这里的provider已经不是JWTauthServiceProvider ], 'aliases' => [ .... 'JWTAuth' => TymonJWTAuthFacadesJWTAuth::class ],
发布配置文件#
php artisan vendor:publish --provider="TymonJWTAuthProvidersLaravelServiceProvider"
php artisan jwt:secret
/**
* Get the value of the model's primary key.
*
* @return mixed
*/
public function getKey()
{
return $this->getAttribute($this->getKeyName());
}
这个一般是得到id
调用Auth::guard('your jwt guard name')->attempt($credentials)
实际是调用了JWTGuard.php里面的attempt方法
oh yeah,终于生成了jwt token了
{"register_result1":"eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJpc3MiOiJodHRwOi8vbGFyYXZlbF9hcGkuYXBwL2FwaS9yZWdpc3RlciIsImlhdCI6MTUwMjM1NjE1MCwiZXhwIjoxNTAyMzU5NzUwLCJuYmYiOjE1MDIzNTYxNTAsImp0aSI6ImJSSHZsUXB5ZzN1WGtTR2MiLCJzdWIiOjksInBydiI6IjM3ODdmYmExNjE4YTkzMDUyNmFjYTZjOGJiOWI0NGI4M2YyOTc3MjYifQ.JpqCVjZggb2BHsCEXzITdnX70HbYIAfQY-iYSpkfHSw"}
$credentials我感觉不应该先用bcrypt,不然attempt会验证失败,只有插入数据库的时候才需要bcrypt
protected function getClaimsForSubject(JWTSubject $subject)
{
return [
'sub' => $subject->getJWTIdentifier(), //主键id
'prv' => $this->hashProvider($subject),
];
}
如何自定义customClaims
public function getJWTCustomClaims()
{
// TODO: Implement getJWTCustomClaims() method.
return ['key1' => 'elesos', 'key2' => 'test'];
}
上面是静态的,如何动态的加呢?
$client = DB::select('select * from clients where email = ?', [$email]);
//return $client;
//var_dump($client);return;//数组里面是对象元素
$customClaims = ['name' => $client[0]->name, 'vip_level' => '1'];
Auth::guard('client')->customClaims($customClaims);
接口如何访问
Route::get('/test1', function () {
return ['state' => 1, 'data' => 'sucess'];
})->middleware('auth:client');
或者
http://api.mysite.com/me?token={yourtokenhere}
验证token信息。
public function validate_test(){
//echo 'validate_test';
//$token = JWTAuth::getToken();
//return $token;
try {
if (! $user = JWTAuth::parseToken()->authenticate()) {
return response()->json(['user_not_found'], 404);
}
} catch (TymonJWTAuthExceptionsTokenExpiredException $e) {
return response()->json(['token_expired'], $e->getStatusCode());
} catch (TymonJWTAuthExceptionsTokenInvalidException $e) {
return response()->json(['token_invalid'], $e->getStatusCode());
} catch (TymonJWTAuthExceptionsJWTException $e) {
return response()->json(['token_absent'], $e->getStatusCode());
}
// the token is valid and we have found the user via the sub claim
return response()->json(compact('user'));
}
下一步要实现错误时返回json,而不是错误页面
Add the following code to the render method within app/Exceptions/Handler.php
public function render($request, Exception $e) { if ($e instanceof TymonJWTAuthExceptionsTokenExpiredException) { return response()->json(['token_expired'], $e->getStatusCode()); } else if ($e instanceof TymonJWTAuthExceptionsTokenInvalidException) { return response()->json(['token_invalid'], $e->getStatusCode()); } return parent::render($request, $e); }
或全部
// 这是我自己错定义的错误
return response()->json(array('error_code' => $e->getStatusCode()));
// 这是默认的错误返回,已注释了
//return parent::render($request, $e);
return response()->json(['errcode' => 4000, 'errmsg' => $exception->getMessage()], 200);
开发环境,当 APP_DEBUG = true 时,使用默认错误页面;
生产环境,当 APP_DEBUG = false 时,使用自定义错误页面,异步请求返回json异常信息
修改app/Exceptions/Handler.php
  1. public function render($request, Exception $exception)
  2. {
  3. $debug = config('app.debug', false);
  4. if($debug) {
  5. return parent::render($request, $exception);
  6. }
  7. if ($exception instanceof HttpException) {
  8. $code = $exception->getStatusCode();
  9. $message = $exception->getMessage();
  10. if ($request->expectsJson()) {
  11. return response()->json(['error' => $message], $code);
  12. }
  13. if (view()->exists('errors.custom' . $code)) {
  14. return response()->view('errors.custom' . $code, ['message'=>$message], $code);
  15. }
  16. }
  17. return parent::render($request, $exception);
  18. }
已知laravel5的默认ExceptionsHandler会优先匹配404异常,所以建议在Handler进行处理。
修改app/Exceptions/Handler.phprender方法如下
/** * Render an exception into an HTTP response. * * @param IlluminateHttpRequest $request * @param Exception $exception * @return IlluminateHttpResponse */ public function render($request, Exception $exception) { if (is_a($exception, SymfonyComponentHttpKernelExceptionNotFoundHttpException::class) && $request->expectsJson()) { return response()->json(['msg'=>'NotFound']); } else { return parent::render($request, $exception); } }
原文地址:https://www.cnblogs.com/elesos/p/7344963.html