openjudge 2750

简单计算题
 1 /**
 *2.1 鸡兔同笼问题
 *bailianoj 2750
*/
#include<stdio.h>
void main()
{
    int N;
    int i=0;
    int feet;

    scanf("%d",&N);

    while(i++<N)
    {
        scanf("%d",&feet);
        if(feet%2!=0)
        {
            printf("%d %d
",0,0);
            continue;
        }
        if(feet%4==0)
            printf("%d %d
",feet/4,feet/2);
        else
            printf("%d %d
",(feet-2)/4 + 1,feet/2);
    }
}