平行坐标

简介

总所周知我们所处的地方是3维世界,所以如何直观的显示多维的数据是一个比较困难的事情,所以 主要是项目中要用到~~ ;)

参考链接

https://blog.csdn.net/qq_44702847/article/details/103154088
https://observablehq.com/@d3/parallel-coordinates?collection=@observablehq/visualization

废话不多说 上代码

<!--
 * @Author: your name
 * @Date: 2020-04-26 08:29:53
 * @LastEditTime: 2020-04-26 16:09:36
 * @LastEditors: Please set LastEditors
 * @Description: In User Settings Edit
 * @FilePath: gitlab测试平行坐标index.html
 -->
 <!DOCTYPE html>
<meta charset="utf-8">
<style>
#myau{
  
}
</style>

<body>
  <script src="./d3.js"></script>
  <script src="./index.js"></script>
    <svg id="mysvg"></svg>
    <script>
        // var data = d3.csvParse(await FileAttachment('cars.csv').text() , d3.autoType)// 从服务器拿数据的方式
        var data = [];
        var height = 500;
        
        margin = ({top: 20, right: 10, bottom: 20, left: 10})
       var data =  d3.csv("cars.csv").then(function (d) {

                data = d;
                var keys = data.columns.slice(1)
                data.forEach(element => {
                    for(var i=0; i<keys.length; i++){
                        if(+element[keys[i]] === +element[keys[i]]){
                            element[keys[i]] = +element[keys[i]];
                        }
                    }
                });
                 init();
            }
        )
        function init(){
            var keys = data.columns.slice(1)
            var y = new Map(
                Array.from(
                    keys,
                    key => [key, d3.scaleLinear(d3.extent(data, d => d[key]), [margin.top, height - margin.bottom])]
                )
            )//简历一个比例尺缩放, 对于每个keys所对应的数据从大到小 对应于坐标轴的 长和宽度
        var width = keys.length * 120
        var x = d3.scalePoint(keys, [margin.left+20, width - margin.right - 20])
        var svg = d3.select("#mysvg")
                          .attr("width", width)
                          .attr("height", height)
        for(var i=0; i < keys.length; i++){
            var keyz = keys[i]; 
            var z = d3.scaleSequential(y.get(keyz).domain().reverse(), d3.interpolateRainbow)//d3.interpolateBrBG 配色方案 interpolateRainbow 彩虹图
            svg
                .append('g')
                .attr('fill', 'none')
                .attr('stroke-width', 1.5)
                .selectAll('path')
                .data(data.slice().sort((a, b) => d3.ascending(+a[keyz], +b[keyz])))
                .join('path')
                .attr('stroke', d => z(d[keyz]))
                .attr('stroke-opacity', 0.4)
                .attr('d', d =>// 画线核心
                    d3
                    .line()
                    .defined(([, value]) => value != null)
                    .y(([key, value]) => y.get(key)(value))
                    .x(([key]) => x(key))(d3.cross(keys, [d], (key, a) => [key, a[key]]))
                )
                .append('title')
                .text(d => d.name);

                svg
                .append('g')
                .selectAll('g')
                .data(keys)
                .join('g')
                .attr('transform', d => `translate(${x(d)}, 0)`)
                .each(function(d) {
                    let kee = y.get(d)
                    console.log(kee)
                    d3.select(this).call(d3.axisRight(kee));
                })
                .call(g =>
                    g
                    .append('text')
                    .attr('x', -5 )
                    .attr('y', `${height-5} `)
                    .attr('text-anchor', 'start')
                    .attr('fill', 'currentColor')
                    .text(d => d)
                )
                .call(g =>  // 外边框变白
                    g
                    .selectAll('text')
                    .clone(true)
                    .lower()
                    .attr('fill', 'none')
                    .attr('stroke-width', 5)
                    .attr('stroke-linejoin', 'round')
                    .attr('stroke', 'white')
                );

            }

        }
       
    </script>
</body>

预览图

Hope is a good thing,maybe the best of things,and no good thing ever dies.----------- Andy Dufresne
原文地址:https://www.cnblogs.com/eat-too-much/p/12780403.html