217. Contains Duplicate

Problem:

Given an array of integers, find if the array contains any duplicates.

Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

Example 1:

Input: [1,2,3,1]
Output: true

Example 2:

Input: [1,2,3,4]
Output: false

Example 3:

Input: [1,1,1,3,3,4,3,2,4,2]
Output: true

思路

Solution (C++):

bool containsDuplicate(vector<int>& nums) {
    int n = nums.size();
    sort(nums.begin(), nums.end());
    for (int i = 0; i < n-1; ++i) {
        if (nums[i] == nums[i+1])  return true;
    }
    return false;
}

性能

Runtime: 44 ms  Memory Usage: 9.2 MB

思路

Solution (C++):


性能

Runtime: ms  Memory Usage: MB

相关链接如下:

知乎:littledy

欢迎关注个人微信公众号:小邓杂谈,扫描下方二维码即可

作者:littledy
本文版权归作者和博客园共有,欢迎转载,但未经作者同意必须保留此段声明,且在文章页面明显位置给出原文链接,否则保留追究法律责任的权利。
原文地址:https://www.cnblogs.com/dysjtu1995/p/12595228.html