CodeForces 681B Economy Game (暴力)

题意:给定一个数,问能不能 找到非负 a, b, c,使得 a × 1 234 567 + b × 123 456 + c × 1 234 = n

析:二重循环,去确定c。

代码如下:

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <vector>

using namespace std;
const int aa = 1234567;
const int bb = 123456;
const int cc = 1234;


int main(){
    int n;   scanf("%d", &n);
    bool ok = false;
    for(int i = 0; i * aa <= n; ++i)
        for(int j = 0; i*aa + j*bb <= n; ++j)
            if((n-i*aa-j*bb)%cc == 0) {  puts("YES");  return 0;  }

    puts("NO");
    return 0;
}
原文地址:https://www.cnblogs.com/dwtfukgv/p/5608145.html