HDU 3079 Vowel Counting (水题。。。判断元音)

题意:n个字符串,如果元音就是输出大写,否则输出小写。

析:没啥可说的,只要判断AEIOU就OK了。

代码如下:

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <queue>
#include <vector>
#include <cstring>
#include <map>
#include <cctype>

using namespace std;
const int maxn = 70;
char s[maxn];

bool judge(char ch){
    if('A' == towupper(ch) || 'E' == towupper(ch) || 'I' == towupper(ch) || 'O' == towupper(ch) || 'U' == towupper(ch))
        return true;
    return false;
}

int main(){
    int T;
    scanf("%d", &T);
    while(T--){
        scanf("%s", s);
        int n = strlen(s);
        for(int i = 0; i < n; ++i)
            if(judge(s[i]))  printf("%c", towupper(s[i]));
            else  printf("%c", towlower(s[i]));
        printf("
");
    }
    return 0;
}
原文地址:https://www.cnblogs.com/dwtfukgv/p/5553982.html