Ugly Numbers UVA

2 3 5 循环

第一份代码:

1 #include<stdio.h>
2 int main()
3 {
4     printf("The 1500'th ugly number is 859963392.
");
5     return 0;
6 }
View Code

第二份

 1 #include <iostream>
 2 using namespace std;
 3 #include<stdio.h>
 4 #include<string.h>
 5 #include<math.h>
 6 #include<stack>
 7 int min(int a,int b)
 8 {
 9     return a<b?a:b;
10 }
11 int main()
12 {
13     long long a[1500];
14     long long a2=0,a3=0,a5=0,min1,i;
15     a[0]=1;
16     for(i=1;i<1500;i++)
17     {
18         while(a[a2]*2<=a[i-1])
19             a2++;
20          while(a[a3]*3<=a[i-1])
21             a3++;
22         while(a[a5]*5<=a[i-1])
23             a5++;
24         min1=min(min(a[a2]*2,a[a3]*3),a[a5]*5);
25         a[i]=min1;
26     }
27     cout<<"The 1500'th ugly number is "<<a[1499]<<"."<<endl;
28     return 0;
29 }
View Code
原文地址:https://www.cnblogs.com/dulute/p/7272518.html