Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu
first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
. Note: zero (ling
) must be handled correctly according to the Chinese tradition. For example, 100800 is yi Shi Wan ling ba Bai
.
Input Specification:
Each input file contains one test case, which gives an integer with no more than 9 digits.
Output Specification:
For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.
Sample Input 1:
-123456789
Sample Output 1:
Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
Sample Input 2:
100800
Sample Output 2:
yi Shi Wan ling ba Bai
#include<bits/stdc++.h> using namespace std; const int maxn=100010; char num[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; char wei[5][5]={"Shi","Bai","Qian","Wan","Yi"}; int main(){ string st; cin>>st; int len=st.length(); int left=0,right=len-1; if(st[0]=='-'){ printf("Fu"); left++; } while(left+4<=right){ right-=4; } while(left<len){ bool flag=false; bool isprint=false; while(left<=right){ if(left>0&&st[left]=='0'){ flag=true; } else{ if(flag==true){ printf(" ling"); flag=false; } if(left>0){ printf(" "); } printf("%s",num[st[left]-'0']); isprint=true; if(left!=right){ printf(" %s",wei[right-left-1]); } } left++; } if(isprint==true&&right!=len-1){ printf(" %s",wei[(len-1-right)/4+2]); } right+=4; } return 0; }