将目录结构输出为json格式(zTree)

# -*- coding: UTF-8 -*-
import json,os

path = 'E:\BACKUP'

#返回空目录
def path_to_dict(path):
    d = {'name': os.path.basename(path)}
    if os.path.isdir(path):
        d['type'] = "directory"
        d['children'] = [path_to_dict(os.path.join(path,x)) for x in os.listdir(path)]
    else:
        d['type'] = "file"
    return d

print json.dumps(path_to_dict(path),ensure_ascii=False, indent=2)


#空目录不返回
def path_to_dict(path, my_string=None):
    d = {'name': os.path.basename(path)}
    if os.path.isdir(path):
        d['type'] = "directory"
        d['children'] = []
        paths = [os.path.join(path,x) for x in os.listdir(path)]
        for p in paths:
            c = path_to_dict(p, my_string)
            if c is not None:
                d['children'].append(c)
        if not d['children']:
            return None
    else:
        d['type'] = "file"
    return d

print(json.dumps(path_to_dict('E:\BACKUP'),ensure_ascii=False, indent=2))

实例：将目录转换为zTree使用的json字符串格式

def path_to_dict_filepath(path):
    d = {'name': os.path.basename(path)}
    print path
    if os.path.isdir(path):
        d['type'] = "directory"
        d['children'] = [path_to_dict_filepath(os.path.join(path,x)) for x in os.listdir(path)]
    else:
        d['type'] = "file"
        d['filepath'] = path
    d['nocheck'] = True
    return d

print json.dumps(path_to_dict_filepath(path),ensure_ascii=False)

返回值：：

{"nocheck": true, "type": "directory", "name": "BACKUP", "children": [{"nocheck": true, "type": "directory", "name": "hr-201.9-dbbackup", "children": [{"nocheck": true, "type": "file", "name": "uxinhr.bak"}, {"nocheck": true, "type": "file", "name": "zknet10.bak"}]}, {"nocheck": true, "type": "file", "name": "rsyncd - 副本.rar"}, {"nocheck": true, "type": "file", "name": "部署系统-websites-20160113.rar"}]}

From http://stackoverflow.com/questions/27661247/getting-json-tree-of-folders-and-files-but-only-with-files-containing-given-str