解决js加减乘除精度问题

// 加法
const accAdd = (arg1, arg2) => {
    var r1, r2, m;
    try {
        r1 = arg1.toString().split(".")[1].length;
    }
    catch (e) {
        r1 = 0;
    }
    try {
        r2 = arg2.toString().split(".")[1].length;
    }
    catch (e) {
        r2 = 0;
    }
    m = Math.pow(10, Math.max(r1, r2));
    return (arg1 * m + arg2 * m) / m;
}
// 减法
const subtr = (arg1, arg2) => {
    var r1, r2, m, n;
    try {
        r1 = arg1.toString().split(".")[1].length;
    }
    catch (e) {
        r1 = 0;
    }
    try {
        r2 = arg2.toString().split(".")[1].length;
    }
    catch (e) {
        r2 = 0;
    }
    m = Math.pow(10, Math.max(r1, r2));
     //last modify by deeka
     //动态控制精度长度
    n = (r1 >= r2) ? r1 : r2;
    return ((arg1 * m - arg2 * m) / m).toFixed(n);
}
// 乘法获取准确值 
const accMul = (arg1,arg2) => {
    var m=0,s1=arg1.toString(),s2=arg2.toString();
    try{m+=s1.split(".")[1].length}catch(e){}
    try{m+=s2.split(".")[1].length}catch(e){}
    return Number(s1.replace(".",""))*Number(s2.replace(".",""))/Math.pow(10,m)
}
// 除法获取精确值
const accDiv = (arg1, arg2) => {
    var t1 = 0, t2 = 0, r1, r2;
    try { t1 = arg1.toString().split(".")[1].length } catch (e) { }
    try { t2 = arg2.toString().split(".")[1].length } catch (e) { }
    Math.r1 = Number(arg1.toString().replace(".", ""))
    Math.r2 = Number(arg2.toString().replace(".", ""))
    return (Math.r1 / Math.r2) * Math.pow(10, t2 - t1);
}
export { accAdd, subtr, accMul, accDiv }