将阿拉伯数字的钱转换成汉字

昨天参加一个笔试的时候,遇到这样一个问题:将阿拉伯数字的钱转换成汉字

package com.dorra.jsoup;

import java.math.BigDecimal;

public class ConvertNumber {
  /** 定义数组存放数字对应的大写 */
  private final static String[] STR_NUMBER = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" };

  /** 定义数组存放位数的大写 */
  private final static String[] STR_MODIFY = { "", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟" };

  /**
   * 转化整数部分
   * 
   * @param tempString
   * @return 返回整数部分
   */
  private static String getInteger(String tempString) {
    /** 用来保存整数部分数字串 */
    String strInteger = null;//  
    /** 记录"."所在位置 */
    int intDotPos = tempString.indexOf(".");
    int intSignPos = tempString.indexOf("-");
    if (intDotPos == -1)
      intDotPos = tempString.length();
    /** 取出整数部分 */
    strInteger = tempString.substring(intSignPos + 1, intDotPos);
    strInteger = new StringBuffer(strInteger).reverse().toString();
    StringBuffer sbResult = new StringBuffer();
    for (int i = 0; i < strInteger.length(); i++) {
      sbResult.append(STR_MODIFY[i]);
      sbResult.append(STR_NUMBER[strInteger.charAt(i) - 48]);
    }
    
    sbResult = sbResult.reverse();
    replace(sbResult, "零拾", "零");
    replace(sbResult, "零佰", "零");
    replace(sbResult, "零仟", "零");
    replace(sbResult, "零万", "万");
    replace(sbResult, "零亿", "亿");
    replace(sbResult, "零零", "零");
    replace(sbResult, "零零零", "零");
    /** 这两句不能颠倒顺序 */
    replace(sbResult, "零零零零万", "");
    replace(sbResult, "零零零零", "");
    /** 这样读起来更习惯. */
    replace(sbResult, "壹拾亿", "拾亿");
    replace(sbResult, "壹拾万", "拾万");
    /** 删除个位上的零 */
    if (sbResult.charAt(sbResult.length() - 1) == '零' && sbResult.length() != 1)
      sbResult.deleteCharAt(sbResult.length() - 1);
    if (strInteger.length() == 2) {
      replace(sbResult, "壹拾", "拾");
    }
    /** 将结果反转回来. */
    return sbResult.toString();
  }

  /**
   * 转化小数部分 例:输入22.34返回叁肆
   * 
   * @param tempString
   * @return
   */
  private static String getFraction(String tempString) {
    String strFraction = null;
    int intDotPos = tempString.indexOf(".");
    /** 没有点说明没有小数,直接返回 */
    if (intDotPos == -1)
      return "";
    strFraction = tempString.substring(intDotPos + 1);
    StringBuffer sbResult = new StringBuffer(strFraction.length());
    for (int i = 0; i < strFraction.length(); i++) {
      sbResult.append(STR_NUMBER[strFraction.charAt(i) - 48]);
    }
    return sbResult.toString();
  }

  /**
   * 判断传入的字符串中是否有.如果有则返回点
   * 
   * @param tempString
   * @return
   */
  private static String getDot(String tempString) {
    return tempString.indexOf(".") != -1 ? "点" : "";
  }

  /**
   * 判断传入的字符串中是否有-如果有则返回负
   * 
   * @param tempString
   * @return
   */
  private static String getSign(String tempString) {
    return tempString.indexOf("-") != -1 ? "负" : "";
  }

  /**
   * 将一个数字转化为金额
   * 
   * @param tempNumber 传入一个double的变量
   * @return 返一个转换好的字符串
   */
  public static String numberToChinese(double tempNumber) {
    java.text.DecimalFormat df = new java.text.DecimalFormat("#.#########");
    String pTemp = String.valueOf(df.format(tempNumber));
    StringBuffer sbResult = new StringBuffer(getSign(pTemp) + getInteger(pTemp) + getDot(pTemp) + getFraction(pTemp));
    return sbResult.toString();
  }

  public static String numberToChinese(BigDecimal tempNumber) {
    return numberToChinese(tempNumber.doubleValue());
  }

  /**
   * 替代字符
   * 
   * @param pValue
   * @param pSource
   * @param pDest
   */
  private static void replace(StringBuffer pValue, String pSource, String pDest) {
    if (pValue == null || pSource == null || pDest == null)
      return;
    /** 记录pSource在pValue中的位置 */
    int intPos = 0;
    do {
      intPos = pValue.toString().indexOf(pSource);
      /** 没有找到pSource */
      if (intPos == -1)
        break;
      pValue.delete(intPos, intPos + pSource.length());
      pValue.insert(intPos, pDest);
    } while (true);
  }

  /**
   * @param args
   */
  public static void main(String[] args) {
    System.out.println(numberToChinese(1230400567.8934)+"元");
  }
}
原文地址:https://www.cnblogs.com/dorra/p/7711019.html