遍历1-100 ,如果这个数包含7或者,是7的倍数,则敲桌子
#include <iostream> using namespace std; int main() { for (int i = 1; i < 100; ++i) { if(i % 7 == 0){ cout<< i <<",敲桌子"<<endl; } else{ if(i > 10){ int one = i % 10; int two = i / 10; if( one == 7 || two == 7){ cout<< i <<",敲桌子"<<endl; } } } } return 0; }