sicily 1020 Big Integer

 大数取模，把输入的大数的字符串转换为整数，但同时每一步要取模（老是错在这里），不然就爆了int！
 ----> temp = ((temp * 10) + (s[i]-'0')) % a[j];
 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstring>
 4 #include <stack>
 5 
 6 using namespace std;
 7 
 8 int a[105];
 9 char s[505];
10 
11 int main()
12 {
13     int t;
14     cin >> t;
15     while(t--)
16     {
17     
18         int n;
19         cin >> n;
20         if(n == 0)
21         {
22             cout << "(" << 0 << ")" << endl;
23             continue;
24         }
25         for(int i=0; i<n; i++)
26             cin >> a[i];
27     
28         cin >> s;
29         int len = strlen(s);
30         
31         cout << "(";
32         for(int j=0; j<n; j++)
33         {
34             int temp=0;
35             for(int i=0; i<len; i++)
36                 temp = ((temp * 10) + (s[i]-'0')) % a[j]; //每一步都要取模 
37             
38             if(n == 1)
39                 cout << temp%a[j] << endl;
40             else
41             {
42                 if(j == 0)
43                 {
44                     cout << temp%a[j];
45                     continue;
46                 }
47                     
48                 cout << "," << temp%a[j];
49                 
50             }
51         }
52         cout << ")" << endl;
53     
54         
55     }
56     return 0;
57 }